Answer:

Step-by-step explanation:
Let r be the radius of the semicircle, then 2r is the width of the rectangle. Let y be the length of the rectangle. The perimeter of the window consists of two lengths, one width and length of semicircle, then

Express y:

The area of the window is

Substitute y into the area expression:

Find the derivative A':

Equate A' to 0:

When
then
and the function A is increasing, when
then
and the function A is decreasing. This means that at point
the function A takes it maximal value (the area is maximal).
None of these really fit….. it would be
45/(6+3)
But none of your answers match so I’m not sure,,,,, sorry
Answer:B
Step-by-step explanation:
A. y = 2x-11
B. y = 2x-10
c. y = 2x-4
D. y=2x-2
Recall, the slope intercept equation
y= mx+c
Assuming c is held constant in each scenario
Looking at A
m = 2, c = -11
Equation of the line that passes through the point (3.-4)
-4 = 2×3 + c
c =-10
-10 does not correspond to -11 given
Let's try B
m= 2, c = -10
Equation of the line that passes through the point (3.-4)
-4 = 2×3 + c
c = -4-6 = -10
This intercept correspond with the intercept in B which is -10
Let's look at C
m= 2, c = -4
Equation of the line that passes through the point (3.-4)
-4 = 2×3 + c
c = -4-6 = -10
-10 does not correspond to -4 given
Let's try D
m= 2, c = -2
Equation of the line that passes through the point (3.-4)
-4 = 2×3 + c
c = -4-6 = -10
-10 does not correspond to -2 given