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ycow [4]
2 years ago
13

Please answer need now!!

Mathematics
1 answer:
zvonat [6]2 years ago
5 0

Answer:

1. Too low

2. Too low

3. Too high

4. Too Low

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A church window consisting of a rectangle topped by a semicircle is to have perimeter p . find the radius of the semicircle if t
Y_Kistochka [10]

Answer:

r=\dfrac{p}{4+\pi}

Step-by-step explanation:

Let r be the radius of the semicircle, then 2r is the width of the rectangle. Let y be the length of the rectangle. The perimeter of the window consists of two lengths, one width and length of semicircle, then

p=2y+2r+\pi r.

Express y:

y=\dfrac{p-2r-\pi r}{2}.

The area of the window is

A=y\cdot 2r+\dfrac{1}{2}\pi r^2.

Substitute y into the area expression:

A=\dfrac{p-2r-\pi r}{2}\cdot 2r+\dfrac{1}{2}\pi r^2=pr-2r^2-\pi r^2+\dfrac{1}{2}\pi r^2=pr-2r^2-\dfrac{1}{2}\pi r^2.

Find the derivative A':

A'=p-4r-\pi r.

Equate A' to 0:

p-4r-\pi r=0\Rightarrow r=\dfrac{p}{4+\pi}.

When r then A'>0 and the function A is increasing, when r>\dfrac{p}{4+\pi}, then A' and the function A is decreasing. This means that at point r=\dfrac{p}{4+\pi} the function A takes it maximal value (the area is maximal).

7 0
3 years ago
A. Change the following fractions to mixed numbers.
qaws [65]

Answer:

A )

1 - 1\frac{4}{7}

2 - 5\frac{3}{5}

3 - 3\frac{1}{5}

4 - 4\frac{1}{4}

5 - 6\frac{3}{4}

B )

1 - \frac{1}{4}

2 - \frac{2}{3}

3 - \frac{1}{3}

4 - \frac{4}{25}

5 - \frac{5}{8}

C )

1 - 1

2 - \frac{3}{4}

3 - 1

4 - \frac{3}{4}

5 - \frac{7}{9}

D )

1 - \frac{5}{12}

2 - \frac{2}{3}

3 - \frac{1}{3}

4 - \frac{1}{2}

5 - \frac{5}{12}

6 0
3 years ago
Help? Please?<br><br> Round the number to the thousandths place "79337.945573"
Ivan

\approx79337.946

7 0
3 years ago
Which answer matches this description?
lara31 [8.8K]
None of these really fit….. it would be
45/(6+3)
But none of your answers match so I’m not sure,,,,, sorry
5 0
3 years ago
Which is the equation of a line that passes through the point (3.-4
gtnhenbr [62]

Answer:B

Step-by-step explanation:

A. y = 2x-11

B. y = 2x-10

c. y = 2x-4

D. y=2x-2​

Recall, the slope intercept equation

y= mx+c

Assuming c is held constant in each scenario

Looking at A

m = 2, c = -11

Equation of the line that passes through the point (3.-4)

-4 = 2×3 + c

c =-10

-10 does not correspond to -11 given

Let's try B

m= 2, c = -10

Equation of the line that passes through the point (3.-4)

-4 = 2×3 + c

c = -4-6 = -10

This intercept correspond with the intercept in B which is -10

Let's look at C

m= 2, c = -4

Equation of the line that passes through the point (3.-4)

-4 = 2×3 + c

c = -4-6 = -10

-10 does not correspond to -4 given

Let's try D

m= 2, c = -2

Equation of the line that passes through the point (3.-4)

-4 = 2×3 + c

c = -4-6 = -10

-10 does not correspond to -2 given

7 0
3 years ago
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