I believe the temperature at 11 A.M is 21 degrees
Solve for x in the equation x^2 - 14x + 31 = 63?
<h3><u>Answer:</u></h3>
The value of x for given equation is x = 16 or x = -2
<h3><u>Solution:</u></h3>
Given that equation is
To find: value of "x"
<u>Subtract 63 from both sides we have:</u>
Now we will factor our given quadratic equation by splitting the middle term.
-14x can be splitted as -16x + 2x
<u>Take "x" as common from first two terms and "2" as common from last two terms</u>
<u>Take (x-16) common we have:</u>
Equating the terms to 0,
x - 16 = 0 or x + 2 = 0
x = 16 or x = -2
Therefore, the value of x are: 16 and -2
What are you asking specificaly
The product of the polynomials (3x 2) and (-x3 – 3) is -3x^5-9x²
proof
(3x 2) (-x3 – 3) = -3x^5-9x²
the main rules are as follows:
if we have ax^p multiplying by bx^q, so we can do the calculus as
(ax^p)( bx^q)=(ab)x^p+q