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Dafna1 [17]
2 years ago
8

Which equation best represents the line?

Mathematics
2 answers:
AnnyKZ [126]2 years ago
7 0
The first answer is the correct one
ludmilkaskok [199]2 years ago
5 0
First answer is the correct one
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Rewrite 10 + 12 using the GCF and factoring.
Airida [17]

Answer:

1st option

Step-by-step explanation:

10 + 12 ← factor out 2 ( the GCF of 10 and 12 ) from each term

= 2(5 + 6)

5 0
2 years ago
Find the rate change
Goshia [24]
Rate change is $3.50
4 0
3 years ago
Twenty seven less than eight times a number is equal to five. What is the number?
Korvikt [17]
<h3><u>The unknown number is equal to 4.</u></h3>

8x - 27 = 5

Add 27 to both sides.

8x = 32

Divide both sides by 8

x = 4

6 0
4 years ago
Read 2 more answers
The three angle bisectors of ΔABC intersect at point P. Point P is the
lisabon 2012 [21]
<h3>Answer: C) incenter</h3>

========================================

Explanation:

If you were to intersect the angle bisectors (at least two of them), then you would locate the incenter. The incenter is the center of the incircle which is a circle where it is as large as possible, but does not spill over and outside the triangle. Therefore this circle fits snugly inside the triangle.

--------------

extra notes:

* The centroid is found by intersecting at least two median lines

* The circumcenter is found by intersecting at least two perpendicular bisector lines

* The orthocenter is found by intersecting at least two altitude lines

* The incenter is always inside the triangle; hence the "in" as part of the name. The centroid shares this property as well because the medians are completely contained within any triangle. The other two centers aren't always guaranteed to be inside the triangle.

* The red lines cut each angle of the triangle into two equal or congruent pieces.

5 0
3 years ago
find an equation of the tangent line to the curve at the given point. y=sqrt(x) (1,1) Ive never been good with these equations a
Nady [450]
Equation of a tangent line of a curve is:
y- y0 = f´ (x0) (x - x0 ).   In this case: x0=1, y0=1
f´(x)=\frac{1}{2 \sqrt{x} }(Derivation)
f´(x0)=\frac{1}{2}
y - 1 = 1/2 ( x - 1 )
y - 1 = 1/2 x - 1/2
y = 1/2 x - 1/2 + 1
y =\frac{1}{2}x+ \frac{1}{2}   
4 0
3 years ago
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