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nordsb [41]
2 years ago
14

What is the distance from point E to point D?

Mathematics
2 answers:
Mandarinka [93]2 years ago
6 0

Answer:

6 units

Step-by-step explanation:

could each square from E to D

Nimfa-mama [501]2 years ago
5 0

Answer:

B

Step-by-step explanation:

Looking at the graph, you can see that points E and D are on the same line. The coordinate for point E is (4,-4), and the coordinate for point D is (4,2). Because they are on the same line, we only have to look at the y coordinates, -4 and 2. We add these together (ignoring the negative sign in 4, because distance can't be negative) to get 6, or B.

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What is the surface area of a cube that’s measured 8 inches
MrRa [10]

Answer:

2

Step-by-step explanation:

Haven't done this in awhile but I think it's 2 because if you cube 2 it comes to 8. L x W x H = 8 | 2 x 2 x 2 = 8

7 0
2 years ago
If f(x) = 4x - 20, what is f(4)?
Nataliya [291]

Answer:

f(4) = -4

Step-by-step explanation:

f(x) = 4x - 20

Let x= 4

f(4) = 4*4 - 20

Multiply first

     = 16 -20

Then subtract

    = -4

4 0
3 years ago
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Factor 18x+6y using gcf
Andrew [12]
Group and factor out the greatest common factor then combine. 6(3x+y)
5 0
3 years ago
Write an equation of a line that is perpendicular to the line x-2y=8
Helen [10]

2x+y=8 is the equation perpendicular to x-2y=8.

6 0
3 years ago
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Solve the LP problem. If no optimal solution exists, indicate whether the feasible region is empty or the objective function is
Volgvan

Answer:

(x,y)=(0,7.333)

Step-by-step explanation:

We are required to:

Maximize p = x + 2y subject to

  • x + 3y ≤ 22
  • 2x + y ≤ 14
  • x ≥ 0, y ≥ 0.

The graph of the lines are plotted and attached below.

From the graph, the vertices of the feasible region are:

  • (0,7.333)
  • (4,6)
  • (0,0)
  • (7,0)

At (0,7.333), p=0+2(7.333)=14.666

At (4,6), p=4+2(6)=4+12=16

At (0,0), p=0

At (7,0), p=7+2(0)=7

Since 14.666 is the highest, the maximum point of the feasible region is (0,7.333).

At x=0 and y=7.333, the function p is maximized.

7 0
3 years ago
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