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Dominik [7]
2 years ago
15

Can you guys help with at least one of these two? Thanks!

Mathematics
1 answer:
Finger [1]2 years ago
7 0

Answer:

1) B. -2 hours per person

2) C. 3.60 per pound

Step-by-step explanation:

1)

We can make a slope triangle connecting the points (4, 12) and (10,0)

We get -12/6, or -2 as our slope & final answer

2)

You can do x/y to find the unit rate for this one, or in this case 18/5 = 3.6

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Find the discount price of the item
Nutka1998 [239]
Multiply the amount with the discount

95 x 0.15 = 14.25

Since it is discount, subtract $14.25 from the total amount: $95

95 - 14.25 = $80.75

B) $80.75 is your answer

hope this helps
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Tell me your top 5 songs trying to find some new songs. (Also answering gives you points so yeah pls answer)
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Answer:

Heads Carolina Tails California, Gun Powder and Lead, Ol Red, Daddy's Lesson, Would You Mind

Step-by-step explanation:

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Simplify: (2^2 + 3^4)^-2
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If someone flips switches on the selection in a completely random fashion, what is the probability that the system selected cont
DiKsa [7]
 Given that a display allows a customer to hook together any selection of components, one of each type. These are the types:
Receiver: Kenwood, Onkyo, Pioneer, Sony, Sherwood
CD player: Onkyo, Pioneer, Sony, Technics
Speakers: Boston, Infinity, Polk
Cassette: Onkyo, Sony, Teac, Technics:

Part (a):
In how many ways can one component of each type be selected?

The number of ways one type of receiver will be selected is given by 5C1 = 5
The number of ways one type of CD player will be selected is given by 4C1 = 4
The number of ways one type of speakers will be selected is given by 3C1 = 3
The number of ways one type of cassette will be selected is given by 4C1 = 4

Therefore, the number of ways one component of each type can be selected is given by 5 x 4 x 3 x 4 = 240 ways



Part (b):
In how many ways can components be selected if both the receiver and the compact disc player are to be Sony?

The number of ways of selecting a Sony receiver is 1
The number of ways of selecting a Sony CD player is 1
The number of ways one type of speakers will be selected is given by 3C1 = 3
The number of ways one type of cassette will be selected is given by 4C1 = 4

Therefore, the number of ways components can be selected if both the receiver and the compact disc player are to be Sony is given by 1 x 1 x 3 x 4 = 12



Part (c)
In how many ways can components be selected if none of them are Sony?

The number of ways one type of receiver that is not Sony will be selected is given by 4C1 = 4
The number of ways one type of CD player that is not Sony will be selected is given by 3C1 = 3
The number of ways one type of speakers that is not Sony will be selected is given by 3C1 = 3
The number of ways one type of cassette that is not Sony will be selected is given by 3C1 = 3

Therefore, the number of ways that components can be selected if none of them are Sony is given by 4 x 3 x 3 x 3 = 108



Part (d):
In how many ways can a selection be made if at least one Sony component is to be included?

The total number of ways of selecting one component of each type is 240
The number of ways that components can be selected if none of them are Sony is 108

Therefore, the number of ways of selecting at least one Sony component is given by 240 - 108 = 132



Part (e):
If someone flips switches on the selection in a completely random fashion, what is the probability that the system selected contains at least one Sony component?

The total number of ways of selecting one component of each type is 240
The number of ways of selecting at least one Sony component is 132

Therefore, the probability that a system selected at random contains at least one Sony component is given by 132 / 240 = 0.55



Part (f):
If someone flips switches on the selection in a completely random fashion, what is the probability that the system selected contains exactly one Sony component? (Round your answer to three decimal places.)

The number of ways of selecting only a Sony receiver is given by 1 x 3 x 3 x 3 = 27
The number of ways of selecting only a Sony CD player is given by 4 x 1 x 3 x 3 = 36
The number of ways of selecting only a Sony cassette is given by 4 x 3 x 3 x 1 = 36

Thus, the number of ways of selecting exactly one Sony component is given by 27 + 36 + 36 = 99

Therefore, the probability that a system selected at random contains exactly one Sony component is given by 99 / 240 = 0.413
5 0
4 years ago
In a scale drawing a plane has a length of 35 centimeters. The actual length of the plane is 87.5 feet. What is the scale of the
photoshop1234 [79]
35 cm : 87.5 ft
1 cm : x
cross multiplying
35 cm X = 1 cm x 87.5 ft
x= 87.5 ft. cm /35 cm
x = 2.5 ft
therefore, the scale is 1 cm : 2.5 ft
7 0
3 years ago
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