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Aloiza [94]
2 years ago
8

Solve −2(−4n + 1)+5(25n − 8)=−62. n= ?

Mathematics
2 answers:
Dovator [93]2 years ago
6 0

Answer:

n = 0.15037593985

Step-by-step explanation:

−2(−4n + 1)+5(25n − 8)=−62

8n-2+125n-40= -62

133n = -20

133/133 = 20/133

n = 0.15037593985

This equation might be screwed up; I'd talk to your teacher about it.

In-s [12.5K]2 years ago
5 0
N= -20/133

Step 1: Simplify both sides of the equation.
−
2
(
−
4
n
+
1
)
+
5
(
25
n
−
8
)
=
−
62
(
−
2
)
(
−
4
n
)
+
(
−
2
)
(
1
)
+
(
5
)
(
25
n
)
+
(
5
)
(
−
8
)
=
−
62
(Distribute)
8
n
+
−
2
+
125
n
+
−
40
=
−
62
(
8
n
+
125
n
)
+
(
−
2
+
−
40
)
=
−
62
(Combine Like Terms)
133
n
+
−
42
=
−
62
133
n
−
42
=
−
62
Step 2: Add 42 to both sides.
133
n
−
42
+
42
=
−
62
+
42
133
n
=
−
20
Step 3: Divide both sides by 133.
133
n
133
=
−
20
133
n
=
−
20
133
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Step-by-step explanation:

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Below are three different hypothesis tests about population proportions. For each test, use StatKey and the information given to
Ilia_Sergeevich [38]

Answer:

1a) p-hat=0.38

1b) P=0.08

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2b) P=0.0027

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Step-by-step explanation:

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1a) The p-hat is p-hat=38/100=0.38.

1b) The standard deviation is

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The sample size is n=100.

The z-value is:

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As it is a two-sided test, the p-value considers both tails of the distribution.

The p-value for this |z|=1.74 is P=0.08.

1c) The null hypothesis is not rejected.

(2) H0: p = 0.7 vs Ha: p ≠ 0.7. In their survey, they had a count of 320 using a sample size n=500.

2a) The p-hat is p-hat=320/500=0.64.

2b) The standard deviation is

\sigma=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.7*0.3}{500}}=0.02

The sample size is n=500.

The z-value is:

z=\frac{\hat{p}-p}{\sigma}=\frac{0.64-0.7}{0.02}=\frac{-0.06}{0.02}=-3

As it is a two-sided test, the p-value considers both tails of the distribution.

The p-value for this |z|=3 is P=0.0027.

2c) The null hypothesis is rejected.

(3) H0: p = 0.6 vs Ha: p < 0.6. In their survey, they had a count of 110 using a sample size n=200.

2a) The p-hat is p-hat=110/200=0.55.

2b) The standard deviation is

\sigma=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.6*0.4}{200}}=0.035

The sample size is n=200.

The z-value is:

z=\frac{\hat{p}-p}{\sigma}=\frac{0.55-0.6}{0.035}=\frac{-0.05}{0.035}=-1.43

As it is a two-sided test, the p-value considers both tails of the distribution.

The p-value for this |z|=1.43 is P=0.153.

2c) The null hypothesis is not rejected.

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Keith_Richards [23]
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IceJOKER [234]

Answer:

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2 years ago
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