To finish the table lets see what the differences are between the input (x) and the output (Y)
when input is 32 the output is 20, 32-20 = 12
when input is 14 the output is 2, 14-2 = 12
since the top 2 have the same result, the output is the input minus 12
now that we know that we can finish the table:
when the input is ? the output is -6, so the input = -6 +12 = 6
check: 6-12 = -6 true
when the input is -10, we subtract 12 to get -22 for the output
so the missing input is 6 and the missing output is -22
the function rule would be Y=x-12
c.y+3=f(x) and 0+3 therefore x=3
<span>1. Suppose that a family has an equally likely chance of having a cat or a dog. If they have two pets, they could have 1 dog and 1 cat, they could have 2 dogs, or they could have 2 cats.
What is the theoretical probability that the family has two dogs or two cats?
25% chance
</span><span>2. Describe how to use two coins to simulate which two pets the family has.
</span>
You could use the coins to simulate which pet the family has by flipping them and having head be dog and tails be cat (or vice-versa).
<span>3. Flip both coins 50 times and record your data in a table like the one below.
</span><span>Based on your data, what is the experimental probability that the family has two dogs or two cats?
</span>
Based on the results, I concluded that for Heads, Heads (which could be dogs or cats) there was a 24% chance and for Tails, Tails there was a 26% chance
<span>4. If the family has three pets, what is the theoretical probability that they have three dogs or three cats?
1/8 chance (accidentally messed up there) or 12.5%
</span><span>5. How could you change the simulation to generate data for three pets?
</span><span>
To flip 3 coins and add more spots on the chart.
I hope that this helps because it took a while to write out. If it does, please rate as Brainliest
</span>
$60, Because 2% of $1000 is $20, and 20 x 3 is 60.
