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joja [24]
3 years ago
5

What are the zeros of 3x^2+5x-12

Mathematics
1 answer:
levacccp [35]3 years ago
5 0

Factor the quadratic equation (3x-4)(x+3). Then set the factors equal to zero.

3x-4=0, solve to get 4/3

x+3=0 x=-3

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Read 2 more answers
2^x-1=128<br><br><br> show work pls! thank u :)
hichkok12 [17]

Hello from MrBillDoesMath!

Answer:

Take you pick below!   (either x 8 or x = 7.01, approx, depending how the question is interpreted)




Discussion:

Interpretation 1

If the question is   2^(x -1)  = 128, then as 2^7 = 128,

x-1 = 7 so x = 8



Interpretation 2

If the question is (2^x -1) = 128, then..

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Regards,  

MrB

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<u>d</u><u>i</u><u>f</u><u>f</u><u>e</u><u>r</u><u>e</u><u>n</u><u>c</u><u>e</u><u> </u><u>o</u><u>f</u><u> </u><u>t</u><u>w</u><u>o</u><u> </u><u>n</u><u>u</u><u>m</u><u>b</u><u>e</u><u>r</u><u> </u><u>=</u><u>x-y</u><u> </u><u>is</u><u> </u><u>equal</u><u> </u><u>to</u><u> </u><u>4</u>

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