Answer:
B and C are both correct
Step-by-step explanation:
18/6 = 3
h¹⁰/h¹² = h⁽¹⁰⁻¹²⁾ = h⁻² = 1/h²
the a⁻⁴ term remains unchanged and = 1/a⁴
3a⁻⁴h⁻² =
What are the zeros of 3x^2+5x-12
1 answer:
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Answer:
B and C are both correct
Step-by-step explanation:
18/6 = 3
h¹⁰/h¹² = h⁽¹⁰⁻¹²⁾ = h⁻² = 1/h²
the a⁻⁴ term remains unchanged and = 1/a⁴
3a⁻⁴h⁻² =