The standard form of a quadratic equation is
, while the vertex form is:
, where (h, k) is the vertex of the parabola.
What we want is to write
as
First, we note that all the three terms have a factor of 3, so we factorize it and write:
.
Second, we notice that
are the terms produced by
, without the 9. So we can write:
, and substituting in
we have:
![\displaystyle{ y=3(x^2-6x-2)=3[(x-3)^2-9-2]=3[(x-3)^2-11]](https://tex.z-dn.net/?f=%5Cdisplaystyle%7B%20y%3D3%28x%5E2-6x-2%29%3D3%5B%28x-3%29%5E2-9-2%5D%3D3%5B%28x-3%29%5E2-11%5D)
.
Finally, distributing 3 over the two terms in the brackets we have:
![y=3[x-3]^2-33](https://tex.z-dn.net/?f=y%3D3%5Bx-3%5D%5E2-33)
.
Answer:
Patterns find next 2 numbers 1.) 7,4,1,-2,__,__ <br>
2.) 1,4,9,16,__,__ <br>
3.) 0,1,8,27,__,__
kati45 [8]
Answer:
1. 7, 4, 1, -2, -5, -8
2. 1, 4, 9, 16, 25, 36
3. i'm not sure about this one.
Answer: Polygon Q's area is 1/4 of Polygon P's area
======================================================
Explanation:
Imagine we had a square with side length 8. The area of this square is 8*8 = 64.
Now let's reduce each side of the square by the scale factor 1/2. So each new side is 8*(1/2) = 4. The area of this smaller square is 4*4 = 16.
Comparing the new area (16) to the old one (64), we see that the new area is 16/64 = 1/4 of the old area.
In other words,
new smaller area = (1/4)*(old larger area)
So this is one example to see why (1/2)*(1/2) = 1/4 is the area scale factor based on the linear scale factor of 1/2. In short, (1/2)^2 = 1/4. Whatever the original scale factor is, square it and you'll get the area scale factor.
Answer:
1/3
Step-by-step explanation:
as 1/6 for a one and 1/6 for a 2 and 1/6 + 1/6 is 2/6 or 1/3
Answer:
3 in3
Step-by-step explanation:
1/2 x 1/2 x 1/2=1/8
1/8 x 24= 3
