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2 years ago

If f(x) = x2 - 1 and g(x) = 2x - 3, what is the domain of (fog)(x)?

Mathematics

1 answer:

ladessa [460]2 years ago

4 0

Answer:

domain will be ( -∞, ∞)

Step-by-step explanation:

The given functions are f(x) = x² - 1 and g(x) = 2x - 3

We have to find domain of (fog)(x)

We will find the function (fg)(x) first.

(fog)(x) = f[g(x)]

= (2x - 3)²

= 4x² + 9 - 12x - 1

= 4x² - 12x + 8

= 4 (x² - 3x + 2)

The given function is defined for all values of x.

Therefore, domain will be ( -∞, ∞)

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a radio station had 234 tickets to a concert. They gave away 5 times as many tickets to listeners as to employees. how many tick

RSB [31]

Answer:

39 tickets were given to the employees

Step-by-step explanation:

1. Approach

First, list the given information, then form an equation based on the given information. Finally, solve the equation with simplification and inverse operations.

2.Given

A total of 234 tickets were given away

5 times as many tickets were given away to listeners compared to employees

-Call the number of tickets given away to employees (x)

3. Form an equation

(Tickets_given_to_employees) + (Tickets_given_to_listeners) = (Total_tickets)

Substitute,

x + 5x = 234

Simplify,

6x + 234

Inverse operations,

6x = 234

/6 /6

x = 39

5 0

3 years ago

On Texas Avenue between University Drive and George Bush Drive, accidents occur according to a Poisson process at a rate of thre

Zarrin [17]

Answer:

(a) The probability is 0.6514

(b) The probability is 0.7769

Step-by-step explanation:

If the number of accidents occur according to a poisson process, the probability that x accidents occurs on a given day is:

$P(x)=\frac{e^{-at}*(at)^{x} }{x!}$

Where a is the mean number of accidents per day and t is the number of days.

So, for part (a), a is equal to 3/7 and t is equal to 1 day, because there is a rate of 3 accidents every 7 days.

Then, the probability that a given day has no accidents is calculated as:

$P(x)=\frac{e^{-3/7}*(3/7)^{x}}{x!}$

$P(0)=\frac{e^{-3/7}*(3/7)^{0}}{0!}=0.6514$

On the other hand the probability that February has at least one accident with a personal injury is calculated as:

P(x≥1)=1 - P(0)

Where P(0) is calculated as:

$P(x)=\frac{e^{-at}*(at)^{x} }{x!}$

Where a is equivalent to (3/7)(1/8) because that is the mean number of accidents with personal injury per day, and t is equal to 28 because 4 weeks has 28 days, so:

$P(x)=\frac{e^{-(3/7)(1/8)(28)}*((3/7)(1/8)(28))^{x}}{x!}$