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3 years ago

What is the perimeter?

Mathematics

1 answer:

wlad13 [49]3 years ago

5 0

Answer:

Step-by-step explanation:

Because a^2+b^2=c^2. So 900 plus 5184, then you find the square root.

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PLEASE HURRY Write the equation as a single logarithm 3log(x-2)+2log(x+2)

zubka84 [21]

Answer:

$3\,log (x-2)+2\,log(x+2)$ can be written as the single logarithm:

$log((x-2)^3\,(x+2)^2)$

Step-by-step explanation:

Start by using in both terms of the expression the property of logarithm of a power that states:

$log(a^b)=b\,*\,log(a)$

so we recognize that the factor that multiplies each logarithmic expression, can be understood as the power of the argument of the function logarithm:

$3\,log(x-2)=log((x-2)^3)\\and\\2\,log(x+2)=log((x+2)^2)$

Then we use the property of logarithm of a product which states that:

$log(a*b)=log(a)+log(b)$

So now we recognize the expression:

$log((x-2)^3)\,+\,log((x+2)^2)$

as the logarithm of the product:

$log((x-2)^3\,(x+2)^2)$

which is finally a single logarithm as requested.

5 0

3 years ago

Make A the subject of the formula<br> r=√A/3

aksik [14]

Answer:

A = 9r^2

Step-by-step explanation:

r=√A/3

multiply both sides by 3

3r = √A

Square both sides

3^2 * r^2 = A

9r^2 = A

4 0

3 years ago

What is the equation in the slope intercept form of the line that passes through the point (2,-2) and is perpendicular to the li

Igoryamba

Answer:

Step-by-step explanation:

The slope is 2/5 and the slope of the new line will be -5/2 because the negative reciprocal creates a perpendicular line. Use the point-slope form to write the equation, then simplify and convert into the slope intercept form.

(y--2)=-5/2(x-2)

y+2=-5/2x+10/2

y=-5/2x+5-2

y= -5/2x+3

5 0

4 years ago

Read 2 more answers

Let us suppose that one of the fireworks is launched from the top of the building with an initial upward velocity of 150 ft/s an

ivanzaharov [21]

Answer:

9.6 seconds

Step-by-step explanation:

The equation for projectile motion in feet is $h(t)=-16t^2+v_0t+h_0$ where $v_0$ is the initial velocity in ft/s and $h_0$ is the initial height in feet.

We are given that the initial upward velocity is $v_0=150ft/sec$ and the initial height is $h_0=35ft$ . Thus, plugging these values into our equation, we get $h(t)=-16t^2+150t+35$ as our equation for the situation.

The firework will land, assuming it doesn't explode, when $h(t)=0$ , thus:

$h(t)=-16t^2+150t+35\\\\0=-16t^2+150t+35\\\\t=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\ \\t=\frac{-150\pm\sqrt{150^2-4(-16)(35)}}{2(-16)}\\ \\t=\frac{-150\pm\sqrt{22500+2240}}{-32}\\\\t=\frac{-150\pm\sqrt{24740}}{-32}\\\\t=\frac{-150\pm2\sqrt{6185}}{-32}\\ \\t=\frac{75\pm\sqrt{6185}}{16}\\\\t_1\approx-0.2\\\\t_2\approx9.6$

Since time can't be negative, then the firework will land after 9.6 seconds, assuming it doesn't explode at the time of landing.

3 0

3 years ago

Please answer as many as you can.

dimaraw [331]

Answer: okay so your problems are like 10000000k through out resons of dum. so x=-1. is a little wrong becayse the x = into a 1 so you make the 1 that factor. so thats why answer for 2.5

Step-by-step explanation:

6 0

3 years ago