Ask question

Ask question

All categories

tamaranim1 [39]

2 years ago

5

What is the product?

2 answers:

mrs_skeptik [129]2 years ago

6 0

(2x-3)(4x+5)
2x(4x+5)-3(4x+5)
8x^2 + 10x - 3(4x+5)
8x^2 + 10x - 12x - 15
8x^2 - 2x - 15

sweet-ann [11.9K]2 years ago

4 0

Answer:

C

Step-by-step explanation:

(2x-3)(4x+5)

=2x(4x+5)-3(4x+5)

=8x^2+10x-12x-15

=8x^2-2x-15

You might be interested in

Find the sum.172 + (–167) + (–10) + (–144)

Ne4ueva [31]

The answer is negative 149

3 0

3 years ago

Read 2 more answers

M<3 is (3x + 4) and m<5 is (2x +11)

butalik [34]

Answer:

Part 1) Option C. Same side interior angles

Part 2) Option A. $(3x+4)+(2x+11)=180\°$

Part 3) Option B. $m$

Step-by-step explanation:

Part 1) we know that

If p and q are parallel

then

m<3 and m<5 are consecutive interior angles or Same side interior angles

and

$m$

Part 2) we know that

$m$ -----> by consecutive interior angles (supplementary angles)

we have that

$m$

$m$

so

substitute

$(3x+4)+(2x+11)=180\°$

Part 3) Find the measure of angle 5

we know that

$(3x+4)+(2x+11)=180\°$

Solve for x

$5x+15\°=180\°$

$5x=180\°-15\°$

$x=165\°/5\°=33\°$

$m$

substitute the value of x

$m$

8 0

3 years ago

Read 2 more answers

Suppose that \nabla f(x,y,z) = 2xyze^{x^2}\mathbf{i} + ze^{x^2}\mathbf{j} + ye^{x^2}\mathbf{k}. if f(0,0,0) = 2, find f(1,1,1).

lesya [120]

The simplest path from (0, 0, 0) to (1, 1, 1) is a straight line, denoted $C$ , which we can parameterize by the vector-valued function,

$\mathbf r(t)=(1-t)(\mathbf i+\mathbf j+\mathbf k)$

for $0\le t\le1$ , which has differential

$\mathrm d\mathbf r=-(\mathbf i+\mathbf j+\mathbf k)\,\mathrm dt$

Then with $x(t)=y(t)=z(t)=1-t$ , we have

$\displaystyle\int_{\mathcal C}\nabla f(x,y,z)\cdot\mathrm d\mathbf r=\int_{t=0}^{t=1}\nabla f(x(t),y(t),z(t))\cdot\mathrm d\mathbf r$

$=\displaystyle\int_{t=0}^{t=1}\left(2(1-t)^3e^{(1-t)^2}\,\mathbf i+(1-t)e^{(1-t)^2}\,\mathbf j+(1-t)e^{(1-t)^2}\,\mathbf k\right)\cdot-(\mathbf i+\mathbf j+\mathbf k)\,\mathrm dt$

$\displaystyle=-2\int_{t=0}^{t=1}e^{(1-t)^2}(1-t)(t^2-2t+2)\,\mathrm dt$

Complete the square in the quadratic term of the integrand: $t^2-2t+2=(t-1)^2+1=(1-t)^2+1$ , then in the integral we substitute $u=1-t$ :

$\displaystyle=-2\int_{t=0}^{t=1}e^{(1-t)^2}(1-t)((1-t)^2+1)\,\mathrm dt$

$\displaystyle=-2\int_{u=0}^{u=1}e^{u^2}u(u^2+1)\,\mathrm du$

Make another substitution of $v=u^2$ :

$\displaystyle=-\int_{v=0}^{v=1}e^v(v+1)\,\mathrm dv$

Integrate by parts, taking

$r=v+1\implies\mathrm dr=\mathrm dv$

$\mathrm ds=e^v\,\mathrm dv\implies s=e^v$

$\displaystyle=-e^v(v+1)\bigg|_{v=0}^{v=1}+\int_{v=0}^{v=1}e^v\,\mathrm dv$

$\displaystyle=-(2e-1)+(e-1)=-e$

So, we have by the fundamental theorem of calculus that

$\displaystyle\int_C\nabla f(x,y,z)\cdot\mathrm d\mathbf r=f(1,1,1)-f(0,0,0)$

$\implies-e=f(1,1,1)-2$

$\implies f(1,1,1)=2-e$

3 0

3 years ago

What is the area of this parallelogram? A = 20 ft² A=2123 ft² A=3313 ft² A=4123 ft².

cluponka [151]

Answer:

Step-by-step explanation:

where's the parallelogram?

4 0

2 years ago

Tarin organized this table to determine the number of adults a and children attending a fundraiser based on the total number of

GarryVolchara [31]

Answer:

I don't see any answer choices.

6 0

3 years ago

Read 2 more answers