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dexar [7]
2 years ago
10

Solve this math problem. Correct answer gets brainliest.

Mathematics
1 answer:
gtnhenbr [62]2 years ago
5 0

Answer:

$28.50

Step-by-step explanation:

21 ÷ 14 = 1.5

19 · 1.5 = 28.50

Hope this helps!!

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32 + (7 − 2) ⋅ 4 − 6 over 3.
Oliga [24]
15.3 the 3 repeats itself FOREVER
3 0
3 years ago
Read 2 more answers
Help ASAP with these
Fittoniya [83]

Answer:

Therefore the correct assembling is

3.∠DAC ≅ ∠BCA    3. Alternate interior Angles are Equal as AD || BC.

Step-by-step explanation:

Given:

AD ≅ BC and AD || BC

To Prove:

ABCD is a Parallelogram

Proof:

Alternate Interior Angles Theorem :

"When two parallel lines are cut by a transversal , the resulting alternate interior angles are congruent.

Here AD || BC and the transversal is AC

  Statement               Reasons

1. AD ≅ BC  .           1. Given

2. AD || BC              2. Given

3.∠DAC ≅ ∠BCA    3. Alternate interior Angles are Equal as AD || BC.

Therefore the correct assembling is

3.∠DAC ≅ ∠BCA    3. Alternate interior Angles are Equal as AD || BC.

4 0
3 years ago
Can someone help solve 1 + 2x = 7?​
Yanka [14]

Answer:

3

Step-by-step explanation:

1+2x=7

7-1=6

2x=6

6/2=3

x=3

5 0
3 years ago
Read 2 more answers
Cual es resultado de 8.5 × 10^4 - 3.0 × 10^3
Veronika [31]
Simplify 10^4 to 10000

8.5x10000-3.0x10^3

Simplify 8.5x*10000 to 85000x
85000x-3.0*10^3
Simplify 3.0x10^3 to 3*10^3
Answer 85000x-3*10^3
5 0
3 years ago
I need help writing the first 5 terms of the sequence!
Angelina_Jolie [31]

The first five terms of the sequence are 1, 4, 7, 10, 13.

Solution:

Given data:

a_{1}=1

a_{n}=a_{n-1}+3

General term of the arithmetic sequence.

a_{n}=a_{n-1}+d, where d is the common difference.

d = 3

a_{n}=a_{n-1}+3

Put n = 2 in a_{n}=a_{n-1}+3, we get

a_{2}=a_1+3

a_{2}=1+3

a_2=4

Put n = 3 in a_{n}=a_{n-1}+3, we get

a_{3}=a_2+3

a_{3}=4+3

a_3=7

Put n = 4 in a_{n}=a_{n-1}+3, we get

a_{4}=a_3+3

a_{4}=7+3

a_4=10

Put n = 5 in a_{n}=a_{n-1}+3, we get

a_{5}=a_4+3

a_{5}=10+3

a_5=13

The first five terms of the sequence are 1, 4, 7, 10, 13.

3 0
3 years ago
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