All categories

3 years ago

Cual es resultado de 8.5 × 10^4 - 3.0 × 10^3

1 answer:

5 0

Simplify 10^4 to 10000

8.5x10000-3.0x10^3

Simplify 8.5x*10000 to 85000x
85000x-3.0*10^3
Simplify 3.0x10^3 to 3*10^3
Answer 85000x-3*10^3

You might be interested in

A line passes through the points (-4,n) and (2,4n) and has the slope of 6. What’s the value of n?

Wittaler [7]

Not sure about this one sorry bud

4 0

3 years ago

A dartboard consists of a circle inscribed in a square. The area of the circle is 16π square centimeters. The area of the square

lapo4ka [179]

The solution would be like this for this specific problem:

Area of Circle = 16(π)

= 16 * 3.14

= 50.24

Area of Square = 64

= 64 – 50.24

= 13.76

Area of Square but not on the circular board = 13.76 / 64

= 0.215

Percentage value = 0.215 * 100%

= 21.5%

So, <span>to the nearest percent, the probability that the dart lands inside the square but not on the circular dartboard is 21.5%.</span>

4 0

3 years ago

Read 2 more answers

Solve for x:

galina1969 [7]

division to 4 is the last step

8 0

2 years ago

A grocery store buys items and then applies a markup of 70%. What is the retail price of item that originally costs $10?

S_A_V [24]

Answer:

$17.00

Step-by-step explanation:

10 x 1.70 = $17.00

8 0

2 years ago

Read 2 more answers

Which of the following ordered pairs is not a solution of the system of inequalities? y > x2 – 4x – 5 y < –x2 – 5x + 6 Que

horrorfan [7]

Answer:

a) (x, y) = (1, 7)

Step-by-step explanation:

Let be the following system of inequalties:

$y > x^{2}-4\cdot x -5$

$y < -x^{2}-5\cdot x +6$

We can find the right option by evaluating each option in the system of inequalities:

a) (x, y) = (1, 7)

$7 > 1^{2}-4\cdot (1) -5$

$7 < -1^{2}-5\cdot (1) +6$

Then,

$7>-8$ (TRUE)

$7$ (FALSE)

(1, 7) is not a solution of the system of inequalities.

b) (x, y) = (1, -7)

$-7 > 1^{2}-4\cdot (1) -5$

$-7 < -1^{2}-5\cdot (1) +6$

Then,

$-7 > - 8$ (TRUE)

$-7< 0$ (TRUE)

(1, -7) is a solution of the system of inequalities.

c) (x, y) = (1, -5)

$-5 > 1^{2}-4\cdot (1) -5$

$-5 < -1^{2}-5\cdot (1) +6$

Then,

$-5 > - 8$ (TRUE)

$-5< 0$ (TRUE)

(1, -5) is a solution of the system of inequalities.

d) (x, y) = (-1, 6)

$6 > (-1)^{2}-4\cdot (-1) -5$

$6$

Then,

$6>0$ (TRUE)

$6 < 12$ (TRUE)

(-1, 6) is a solution of the system of inequalties.

Therefore, we conclude that correct answer is A.

4 0

3 years ago