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mixer [17]
2 years ago
6

What would be the 67th term in this sequence

Mathematics
2 answers:
SIZIF [17.4K]2 years ago
8 0
<h2>Answer : 268</h2>

<h3>Step by step explanation:</h3>

Given sequence = 4,8,12,16...., (t1,t2,t3,t4,......)

first term(a) = 4

Common difference(d) = t2-t1 = 8-4 = 4

nth term of arhmetic sequence is given by,

tn = a+(n-1)d

To calculate the 67th term(t67) of sequence substitute n = 67,a = 4,d = 4 in above formula,

t67= 4+ (67-1)×(4)

t67 = 4+ 66×4

t67 = 4+264

t67 = 268

The 67th term of sequence is 268

Thanks for joining brainly community.

rodikova [14]2 years ago
3 0

<u>Answer:</u>

  • The 67th term in the sequence is 268.

<u>Step-by-step explanation:</u>

<u>We will use the formula 4(x), where x is the number of terms.</u>

In this question, it says to find the 67th term. Let's substitute 67 into the formula to obtain our answer.

  • 4(x)
  • => 4(67)
  • => 268

Hence, <u>the 67th term in the sequence is 268.</u>

Hoped this helped.

BrainiacUser1357

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