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2 years ago

6

What is the answer to this?

2 answers:

Arlecino [84]2 years ago

6 0

count all tiles and note

x^2=8
x=9
1=3

Now multiply and add

$\\ \sf\longmapsto 8(x^2)+9(x)+3(1)$

$\\ \sf\longmapsto 8x^2+9x+3$

Sholpan [36]2 years ago

3 0

Answer:

Solution given;

There are 8*x² , 6 *x and 3 *1.

So

in total it is <u>8x²+6x+3</u> which is a required expression.

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-x+1,4 <0<br> f(x)= -2,x=0<br> x2-1, x > 0

Blababa [14]

Answer:

Step-by-step explanation:

That is not something you can do it would be a large number

5 0

3 years ago

A kite gets stuck at the top of a vertical tree. The kite's 15 m string

Georgia [21]

Are you good it’s 73.33

8 0

3 years ago

Write in slope-intercept form an equation of the line that passes through the given points. (2,4),(5,13)

antiseptic1488 [7]

Answer:

y = 3x-2

Step-by-step explanation:

We can find the slope using the equation for slope

m = (y2-y1)/(x2-x1)

= (13-4)/(5-2)

= 9/3

= 3

We know the slope and a point, so we can use point slope form to make an equation

y-y1 = m(x-x1)

y-4 = 3(x-2)

Distribute

y-4 = 3x-6

Add 4 to each side

y-4+4 = 3x-6+4

y = 3x-2

This is in slope intercept form (y= mx+b)

7 0

3 years ago

How do you Subtract 9x^2 + 22x - 46 from 12x^2 - 8x + 12.

Luba_88 [7]

Subtract the $x^2$ terms from each other, then the $x$ terms, then the ones without any $x$ whatsoever.

$(12x^2 - 8x + 12) - (9x^2 +22x-46)$

First, we'll subtract $9x^2$ from $12x^2$

$12x^2-9x^2- = 3x^2$

Result: $3x^2$

Next, we'll subtract $22x$ from $-8x$

$-8x - 22x = -30x$

Result: $-30x$

Finally, we'll subtract $-46$ from $12$

$12-(-46) = 12+46 = 58$

Result: $58$

Now, we can add these 3 results together.

First, we had $3x^2$ , then $-30x$ , and finally $58$ .

Thus, our subtraction of

$(12x^2 - 8x + 12) - (9x^2 +22x-46)$

equals

$3x^2-30x+58$

4 0

3 years ago

A buoy floating in the sea is bobbing in simple harmonic motion with period 2 seconds and amplitude 8 in. Its displacement d fro

Mrac [35]

Answer:

The equation of the displacement $d$ as a function of time $t$ is :

$d(t)=8sin(\pi t+\pi )$

Step-by-step explanation:

Generally , A simple harmonic wave is a sinusoidal function that is it can be expressed in simple $sin$ or $cos$ terms.

Thus,

$d(t) = Asin(wt+c)$

is the general form of displacement of a SHM.

where,

<em> $d(t)$ is the displacement with respect to the mean position at any time $t$ </em>
<em> $A$ is amplitude </em>
<em> $w$ is the natural frequency of oscillation ( $rads^{-1}$ )</em>
<em> $c$ is the phase angle which indicates the initial position of the object in SHM ( $rad$ )</em>

given,

Time period ( $T$ ) = $2s$
$A=8$
The natural frequency ( $w$ ) and time period ( $T$ ) is :

$w=\frac{2\pi} {T}$

∴

$w$ = $\frac{2\pi }{2} = \pi$ $rads^{-1}$

∴

the equation :

<em>⇒ $d(t)=8sin(\pi t+c)$ </em> ------1

since $d=0$ when $t=o$ ,

<em>⇒ $0=8sinc\\c=n\pi$ ------2</em>

where n is an integer ;

<u>⇒since the bouy immediately moves in the negative direction , $x$ must be negative or c must be an odd multiple of $\pi$ .</u>

<em>⇒ $d(t) = 8sin(\pi t+(2k+1)\pi )$ ------3</em>

where k is also an integer ;

the least value of $k=0$ ;

thus ,

the equation is :

$d(t)=8sin(\pi t+\pi )$

<em></em>

7 0

3 years ago