<span>Write an equation for the line
perpendicular to y = 2x - 5 that contains (-9,6).
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The given line has slope = 2
Any line perpendicular to it must have slope = (-1/2)
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Form:
y = mx + b
Solve for "b":
6 = (-1/2)(-9) + b
6 = (9/2) + b
b = 3/2
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Equation:
y = (-1/2)x + (3/2)</span>
Answer:
a) P(2) = 0.2646
b) P(x > 2) = 0.5334
c) P( 2 <= x < = 5) = 0.7694
Step-by-step explanation:
n = 10
p = 0.27
q = 0.73
x = 10
P(x=0) = (10 C 0 )(0.27^0)(0.73^(10-0)) = 0.043
P(x=1) = (10 C 1 )(0.27^1)(0.73^(10-1)) = 0.159
P(x=2) = 0.2646
P(x=3) = 0.2609
P(x=4) = 0.1689
P(x=5) = 0.075
P(x=6) = 0.0231
P(x=7) = 0.0049
P(x=8) = 0.000677
P(x=9) = 0.0000557
P(x=10) =0.00000206
a) P(2) = 0.2646
b) P(x > 2) = P(3) + P(4) + P(5) + ... + P(10) = 0.5334
c) P( 2 <= x < = 5) = P(2) + P(3) + P(4) + P(5) = 0.7694
X=1.464102
Simplifies to: (1/2x)+1=1.732051
Step 1: Subtract 1 from both sides.
1/2x + 1 -1=1.732051-1
(1/2x)=0.732051
Step 2: Multiply both sides by 2
2*(1/2x) = (2) * (0.732051)
X=1.464102
Answer:
the 1 one and the 4 one
Step-by-step explanation: