Answer:
The equation of the line is y = 3/2x + 5/2
Step-by-step explanation:
To find the equation of this line, start by using the two points with the slope formula to find the slope.
m(slope) = (y2 - y1)/(x2 - x1)
m = (4 - 1)/(1 - -1)
m = 3/(1 + 1)
m = 3/2
Now that we have the slope, we can use that and either point in point-slope form to find the equation.
y - y1 = m(x - x1)
y - 4 = 3/2(x - 1)
y - 4 = 3/2x - 3/2
y = 3/2x + 5/2
Answer:
Step-by-step explanation:
If the position function is
and we are looking for time when the height is 0, we sub in a 0 for h(t) and solve for t:
and the easiest way to do this is to factor by taking the GCF of -40t:
0 = -40t(t - 5) and by the Zero Product Property,
-40t = 0 or t - 5 = 0. Solving for t, we get
t = 0 (which is before the object is launched) and
t = 5 (which is how long it takes the object to go from the ground, up to its max height, and then back to the ground again).
Your choice is c) 5
Answer:
0.24
Step-by-step explanation:
Answer:
m+p/2=n
Step-by-step explanation:
You can't get any other multiplication factor, so the only way is to isolate n, by adding p to m and dividing by 2