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vova2212 [387]
3 years ago
7

if powerades are $2.50 and nachos are $3 there was 38 items sold and the total price was $102.50 how many powerades and nachos w

ere sold
Mathematics
1 answer:
Oksana_A [137]3 years ago
5 0

Answer:

15 Nachos and 23 Powerades were sold.

Brainliest is appreciated. (The crown)

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1. The sum of the real numbers x and y is 15. Their
Brut [27]

Answer:

x = 9

y = 6

Step-by-step explanation:

Let's set up equations:

x + y = 15

x - y = 3

Let's rearrange one of these equations to use the substitution method:

x - y = 3

Add y to each side:

x = y + 3

Substitute in for x:

x + y = 15

y + 3 + y = 15

Combine like terms:

( y + y ) + 3 = 15

2y + 3 = 15

Subtract 3 from each side:

2y = 12

Divide each side by 2:

y = 6

Substitute this in to find the other variable:

x + y = 15

x + 6 = 15

Subtract 6 from each side:

x = 9

6 0
2 years ago
Help help HELLLP help help help
m_a_m_a [10]

Answer:

If you use the 3x to the 2y is will make more sense if u turn them into numbers instead of letters cause letters dont make much sense somtimes.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What is the product of (3√8)(4√3)? Simplify your answer
andreyandreev [35.5K]
The answer is:  24√6 .
_______________________________
The question asks:
_______________________________
"<span>What is the product of (3√8)(4√3)? Simplify your answer/

First, let us simplify:  "</span>√8" 

"√8 = √4*√2 = 2√2 ;

So, "3√8 = 3*2√2 = 6√2" .

So, "what is the product of "(3√8)(4√3)"?  

Rewrite, replacing the "(3√8)" with "6<span>√2" ; as follows:

</span>6√2* 4√3 = 6*4 *√2*√3 = 24 *√(2*3) = 24√6 . 
______________________________________
3 0
3 years ago
Write the quadratic equation that has roots -1-rt2/3 and -1+rt2/3 if its coefficient with x^2 is equal to 1
weeeeeb [17]

The equation of the quadratic function is f(x) = x²+ 2/3x - 1/9

<h3>How to determine the quadratic equation?</h3>

From the question, the given parameters are:

Roots = (-1 - √2)/3 and (-1 + √2)/3

The quadratic equation is then calculated as

f(x) = The products of (x - roots)

Substitute the known values in the above equation

So, we have the following equation

f(x) = (x - \frac{-1-\sqrt{2}}{3})(x - \frac{-1+\sqrt{2}}{3})

This gives

f(x) = (x + \frac{1+\sqrt{2}}{3})(x + \frac{1-\sqrt{2}}{3})

Evaluate the products

f(x) = (x^2 + \frac{1+\sqrt{2}}{3}x + \frac{1-\sqrt{2}}{3}x + (\frac{1-\sqrt{2}}{3})(\frac{1+\sqrt{2}}{3})

Evaluate the like terms

f(x) = x^2 + \frac{2}{3}x - \frac{1}{9}

So, we have

f(x) = x²+ 2/3x - 1/9

Read more about quadratic equations at

brainly.com/question/1214333

#SPJ1

7 0
1 year ago
Plsss help I’ll give u brainlest and 5 or 10 points pls
Svetach [21]

Answer:

No

Step-by-step explanation:

That is not enough,that is why it is a no

PLs mark brainly

Hope this helps:)

8 0
3 years ago
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