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Vsevolod [243]
3 years ago
11

$\triangle DEF$ is the medial triangle of $\triangle ABC$ and $\triangle XYZ$ is the medial triangle of $\triangle DEF.$ If the

perimeter of $\triangle XYZ$ is $5$, what is the perimeter of $\triangle ABC
Mathematics
1 answer:
lbvjy [14]3 years ago
6 0

A medial triangle is made from the midlines of the larger triangle, and its

length is half the length of the third side of the triangle.

  • The perimeter of ΔABC is <u>20</u>

Reasons:

The medial triangle of triangle ΔABC is triangle ΔDEF

The medial triangle of  ΔDEF is ΔXYZ

The perimeter of ΔXYZ = 5

By the midpoint theorem, we have;

The lengths of the sides of ΔDEF = 0.5 × The lengths of the sides of ΔABC

∴ The perimeter of ΔDEF = 0.5 × The perimeter of ΔABC

Which gives;

The perimeter of ΔABC = 2 × The perimeter of ΔDEF

Similarly, between ΔXYZ and ΔDEF, we have;

The perimeter of ΔDEF = 2 × The perimeter of ΔXYZ

∴ The perimeter of ΔDEF = 2 × 5 = 10

Therefore;

The perimeter of ΔABC = 2 × 10 = 20

<u>The perimeter of ΔABC = 20</u>

Learn more about the perimeter of a triangle here:

brainly.com/question/1340753

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The distribution of passenger vehicle speeds traveling on a certain freeway in California is nearly normal with a mean of 71.5 m
Zinaida [17]

Answer:

a

G  =   0.007523

b

 The  number of cars the  highway patrol officer would watch before a  car that is seen is E(X) = 1.6027

The standard deviation is   s  =  0.9829

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Step-by-step explanation:

From the question we are told that

The mean is \mu  =  71.5 \ miles/hour

The standard deviation is \sigma  =  4.75 \  miles/hour

The speed limit is x =  70 \  miles /hour

Generally the probability of getting a car that is moving with speed greater than the speed limit is mathematically represented as

p =P(X > x  )  =  P(X > 70) =  P(\frac{X - \mu }{\sigma }  >  \frac{70 - 71.5 }{4.75})

=> p=  P(X > 70) =  P(\frac{X - \mu }{\sigma }  >  \frac{70 - 71.5 }{4.75})

=> p= P(X > 70) =  P(\frac{X - \mu }{\sigma }  >  -0.31579 )

Here

\frac{X - \mu }{\sigma }  =  Z(The \ standardized \  value  \ of  X )

So

=> p=  P(X > 70) =  P(Z >  -0.31579 )

From the z-table

p = P(Z >  -0.31579 ) =   0.62392

So

p =  P(X > 70) =  0.62392

Generally the probability of getting a car that is not moving with speed greater than the speed limit is mathematically represented as

q =  1 - p

=> q =  1 -  0.62392

=> q =  0.37608

Generally the probability of getting 5 cars that are not speeding is mathematically represented as

G  =  q^5

=> G  =  (0.37608)^5

=> G  =   0.007523

Generally the number of cars that the highway patrol officer is expected to watch until the first car that is speeding is gotten is mathematically represented as

E(X) =  \frac{1}{p}

=> E(X) =  \frac{1}{0.62392}

=> E(X) = 1.6027

Generally the standard deviation is mathematically represented as

s  =  \sqrt{\frac{1 - p }{ p^2} }

=>     s  =  \sqrt{\frac{1 -0.62392 }{ (0.62392)^2} }

=> s  =  0.9829

8 0
3 years ago
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