The curve

is parameterized by

so in the line integral, we have





You are mistaken in thinking that the gradient theorem applies here. Recall that for a scalar function

, we have gradient

. The theorem itself then says that the line integral of

along a curve

parameterized by

, where

, is given by

Specifically, in order for this theorem to even be considered in the first place, we would need to be integrating with respect to a vector field.
But this isn't the case: we're integrating

, a scalar function.
Answer:
m+p-n
Step-by-step explanation:
given that Jerry manages a local car dealership. At the beginning of the month, his lot had m vehicles. During the month his salesman sold n vehicles, and he purchased p vehicles more
We are to find the number of vehicles did the dealership have at the end of the month
At the end of the month the dealer would have
no of vehicles at the start of the month- sales of the vehicle in that month+Purchase of vechicles during that month
No of vehicles at the start of the month = m
Purchase during month =p
Total vehicles including purchase = m+p
LESS: Vehicles sold in the month = n
No of vehicles at the end = m+p-n
♦Which figure has all sides of equal measure but not necessary all angles of equal measure?
Ans: H. Rhombus.
♦Which shape must have opposite sides that are parallel and congruent, and diagonals that are perpendicular bisectors of each other?
Ans: A) Parallelogram.
♦In rectangle ABCD, the slope of.........
Ans: 1/2
Ans:
If sqrt x = 9 then x = 9*9 = 81
Answer is between 80 and 90.
I have solved some examples in the picture
If anything is unclear let me know.
:)