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vovikov84 [41]
2 years ago
6

This is Math but I still need help!!!!

SAT
1 answer:
zaharov [31]2 years ago
3 0
Photo is pixilated! Please put up a better copy!

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A 20.0-ml sample of a 0.200 mhbr solution is titrated with a 0.200 mnaoh solution. calculate the ph of the solution after the fo
kumpel [21]

The calculated pH of the solutions are given below:

  • The pH of the solution after 14.0 ml of base is added to it is calculated as 1.45.
  • The pH of the solution after 19.8 ml of base is added to it is calculated as 3.0
  • The pH of the solution after 20.0 ml of base is added to it is calculated as 7.

<h3>What is pH?</h3>

This is the level of acidity or alkalinity of an aqueous solution. The pH of a substances tells if its an acid, base or neutral.

HBr and NaOH while in water would dissociate and they would become H+ and OH- respectively.

Mol of HBr = Mol * Vol

= 0.200 * 20mL

= 4 mmol

A. Moles of NaOH added

= 0.2 X 14

= 2.8 mmol

Moles of H+ that did not react

= 4 - 2.8

= 1.2 mmol

1.2/1000 = 0.0012 moles

Total volume = 20 + 14

= 34 mL to litres

= 0.034 L

Molarity of H+ = 0.0012 / 0.034L

= 0.035 M

-log[0.035] = 1.45

The pH of the solution is  1.45

B. NaOH added = 19.8 * 0.2 =

3.96 mmoles

The unreacted solution

= 4.0 - 3.96

= 0.04 mmol

0.04/1000 = 0.00004 moles

Total volume = 20 + 19.8

= 39.8mL

Converted to litres = 0.0398L

Molarity  = 0.00004 / 0.0398L

= 0.001

-log(0.001) = 3.0

The ph Is therefore 3.0

C. Moles of NaOH added = 0.2*20mL = 4mmol

All the H+ are going to be consumed here. This would result into a neutral solution pH = 7

<u>Complete question:</u>

20.0 mL sample of 0.200 M HBr solution is titrated with 0.200 M NaOH solution. Calculate the PH of the solution after the following volumes of base have been added.

A. 14.0 mL

B. 19.8 mL

C. 20.0 mL

Read more on pH here; brainly.com/question/22390063

3 0
2 years ago
How to add maths??? teacher gave question me to!:
Law Incorporation [45]

Answer:

The answer is 4

Explanation:

7 0
3 years ago
Read 2 more answers
(5372 + 100y^2) + 5(10y^2 – 110) Add the two polynomials and write in the form ay^2 + b, where a and b are constants, What is th
dangina [55]

Answer:

The value of a is 150 and b is 4822.

Explanation:

First, you have to expand to remove brackets :

(5372 + 100 {y}^{2} ) + 5(10 {y}^{2}  - 110)

= 5372 + 100 {y}^{2}  + 50 {y}^{2}  - 550

Next, you have to simplify :

100 {y}^{2}  + 50 {y}^{2}  + 5372 - 550

= 150 {y}^{2}  + 4822

Next, you have to compare it :

a {y}^{2}  + b = 150 {y}^{2}  + 4822

a = 150

b = 4822

5 0
3 years ago
Which organization would be considered a nonbank institution
inna [77]

The  organization that would be considered a nonbank institution is b) Missouri Public School Retirement System.

<h3>What is nonbank institution?</h3>

A non-banking financial institution  can be regarded as  financial institution that does not have a full banking license .

In this case, The  organization that would be considered a nonbank institution is b) Missouri Public School Retirement System.

CHECK THE COMPLETE QUESTION BELOW:
Which of the following organizations would be considered a nonbank institution?

a) Educational Employees Credit Union

b) Missouri Public School Retirement System

c) Southwest Savings Bank

d) Heartland Bank

Learn more about nonbank institution on:

brainly.com/question/16026225

#SPJ1

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