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3 years ago

Which of the following is a skill that will aid students in preparing for a test.

SAT

2 answers:

Oksi-84 [34.3K]3 years ago

3 0

C knowing how to dissect a test and the questions

rodikova [14]3 years ago

3 0

C is the correct answer

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A company purchased manufacturing equipment 5 years ago for $50,000. book value is currently $5,000 and the remaining useful lif

GalinKa [24]

Since purchasing new gear will reduce cash flow by $5,000, the corporation should keep its old equipment, and the calculation can be defined as follows:

<h3 /><h3>Calculating the Total decrease in net income:</h3>

The following are the costs if the company keeps the old equipment:

$\to$ $30,000 x 3 years = $90,000 So, the total cost is $90,000.

The following are the costs if the company purchases new equipment:

Calculating the equipment cost that is

$\to$ $75,000 - $10,000 = $65,000.

$\to$ $10,000 x 3 years = $30,000. So, the total cost is $95,000.

Find out more about the total decrease in net income here: here:brainly.com/question/10955397

5 0

2 years ago

Read 2 more answers

You are driving on a two-lane highway and the vehicle behind you wants to pass. You should

fenix001 [56]

Pull over and let the car behind you pass

5 0

3 years ago

Read 2 more answers

Determine whether or not the vector field is conservative. If it is conservative, find a function f such that f = ∇f. (if the ve

Arisa [49]

If F(x, y, z) = i + sin(z) j + y cos(z) k is conservative, then there exists a scalar function f(x, y, z) such that grad(f) = F, which means

∂f/∂x = 1

∂f/∂y = sin(z)

∂f/∂z = y cos(z)

Integrating each each of these equations gives

∫ ∂f/∂x dx = ∫ dx ⇒ f(x, y, z) = x + α(y, z)

∫ ∂f/∂y dy = ∫ sin(z) dy ⇒ f(x, y, z) = y sin(z) + β(x, z)

∫ ∂f/∂z dx = ∫ y cos(z) dz ⇒ f(x, y, z) = y sin(z) + γ(x, y)

It follows that α(y, z) = y sin(z) and β(x, z) + γ(x, y) = x + C where C is a constant. So

f(x, y, z) = x + y sin(z) + C

and F is indeed conservative.

6 0

3 years ago

To compare the average amount of time that canadians and americans spend commuting, a researcher collects a sample of canadians

yKpoI14uk [10]

The standard error of the difference of sample means is 0.444

From the complete question, we have the following parameters

<u>Canadians</u>

Sample size = 50
Mean = 4.6
Standard deviation = 2.9

<u>Americans</u>

Sample size = 60
Mean = 5.2
Standard deviation = 1.3

The standard error of a sample is the quotient of the standard deviation and the square root of the sample size.

This is represented as:

$SE = \frac{\sigma}{\sqrt n}$

The standard error of the Canadian sample is:

$SE_1 = \frac{2.9}{\sqrt{50}}$

So, we have:

$SE_1 = 0.41$

The standard error of the American sample is:

$SE_2 = \frac{1.3}{\sqrt{60}}$

So, we have:

$SE_2 = 0.17$

The standard error of the difference of sample means is then calculated as:

$SE= \sqrt{SE_1^2 + SE_2^2}$

This gives

$SE= \sqrt{0.41^2 + 0.17^2}$

$SE= \sqrt{0.197}$

Take square roots

$SE= 0.444$

Hence, the standard error of the difference of sample means is 0.444