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aivan3 [116]
2 years ago
14

Maths.................​

Mathematics
2 answers:
Schach [20]2 years ago
6 0
Wsp just do the thing man i have no idea
AlekseyPX2 years ago
6 0
If it’s according to the trigonometry law then
(a) x = 5
(b) x = 10
(c) x= 13

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Select the correct answer
Tomtit [17]

Answer:

Step-by-step explanation:

The area for a triangle is

A=\frac{1}{2}bh

Our base is given as x, the height is given as 1 more than 6 times the base which looks like this: 6x + 1. We know that the area is 13, so filling in everything:

13=\frac{1}{2} (6x+1)(x)

We can get rid of the denominator of 2 by multiplying it on both sides to get:

26=(6x+1)(x) and simplifying a bit:

26=6x^2+x

Now we can move over the 26 and put the expression into standard quadratic form by setting it equal to 0:

6x^2+x-26=0 which is choice C

3 0
2 years ago
Solve the system of linear equations.<br> y = -2x - 4<br> y = 2x – 4.
creativ13 [48]

good luck! :D

have a nice day/night

6 0
3 years ago
Read 2 more answers
Grace read 4 days this week. She read 10 minutes each day. If her teacher wants her to read it a total of 60 minutes, how many m
Slav-nsk [51]

She needs to read 20 more minutes.

10x4=40

60-40=20

4 0
3 years ago
Help me out with these 2 questions for 15 points.
jok3333 [9.3K]

Step-by-step explanation:

The time dilation formula is given by

F(t) = \dfrac{t}{\sqrt{1-v^2}}

where t is the time measured by the moving observer and F(t) is the time measured by the stationary earth-bound observer and <em>v</em><em> </em> is the velocity of the moving observer expressed as a fraction of the speed of light.

a) If the observer is moving at 80% of the speed of light and observes an event that lasts for 1 second, a stationary observer will see the same event occurring over a time period of

F(t) = \dfrac{1\:\text{s}}{\sqrt{1-(0.8)^2}}

\:\:\:\:\:\:\:=\dfrac{1\:\text{s}}{\sqrt{1-(0.8)^2}} =\dfrac{1\:\text{s}}{\sqrt{1-(0.64)}}

\:\:\:\:\:\:\:=1.67\:\text{s}

This means that any event observed by this moving observer will be seen by a stationary observer to occur 67% longer.

b) Given:

t = 1 second

F(t) = 2 seconds

We need to find the speed of the observer such that an event seen by this observer will occur twice as long as seen by a stationary observer. Move the term containing the radical to the left side so the equation becomes

\sqrt{1-v^2} = \dfrac{t}{F(t)}

Take the square of both sides, we get

1 - v^2 =\dfrac{t^2}{F^2(t)}

Solving for <em>v</em>, we get

v^2 = 1 - \dfrac{t^2}{F^2(t)}

or

v = \sqrt{1 - \dfrac{t^2}{F^2(t)}}

Putting in the values for t and F(t) we get

v = \sqrt{1 - \dfrac{(1\:\text{s})^2}{(2\:\text{s})^2}}

v = \sqrt{1 - \dfrac{1}{4}} = \sqrt{0.75}

\:\:\:\:=0.866

This means that the observer must moves at 86.6% of the speed of light.

6 0
3 years ago
She borrows $25.63 from her sister to help pay for the dress. Then Jenny earns $16.33 helping her dad organize his home office.
Mashutka [201]

The answer to this question is: Jenny will still owe her sister $9.30.

25.63 - 16.33 = 9.30

6 0
3 years ago
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