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Irina18 [472]
3 years ago
10

PLEASE HELP!! WILL GIVE BRAINIEST!!! Please solve #7 and #8.

Mathematics
2 answers:
lawyer [7]3 years ago
8 0
7)
slope = (1+3)/(-1+10) = 4/9

y = mx + b
1 = 4/9(-1) + b
b = 1 + 4/9
b = 13/9
equation
y = 4/9x + 13/9

answer is D.y = 4/9x + 13/9

8)
y = 3x - 3
perpendicular so slope = -1/3

passing thru (-7, 9)
equation
y - 9 = -1/3(x +7)

answer is D. y - 9 = -1/3(x +7)
sukhopar [10]3 years ago
3 0
The answer to 7 is:y = (4/9)x + (13/9). 
The answer to 8 is B, I think.
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180 divided into two parts, one part will be 3 times the other part. What is the larger part
Mila [183]
3n + n = 180
4n = 180
n = 180/4 
n = 45

hope it helps, brainliest pls!
7 0
2 years ago
(5×10^5)+(6.182×10^6)<br> Pls answer in scientific notation
dimaraw [331]

Answer:

5.62*10^5

Step-by-step explanation:

5 --> 50; 10^5 --> 106

((50)*(10^6))+(6.182*10^6)

(56.182*10^6)

5.62*10^5

6 0
3 years ago
Graph the line with slope 1/4 and y-intercept -8
kherson [118]

Solution: Below! ^^

Detailed explanation:

Hii! I'm sorry, I can't graph the line for you, but I'll try to give you the best possible explanation.

First, note that the question provides us with the info that the y intercept is -8. This is a very valuable piece of information!

This means that the line crosses the y axis (since it's the y intercept) at the point (0,-8). Plot it on the co-ordinate plane.

Next, this question also provides us with the fact that the slope of the line is 1/4. This is yet another valuable piece of information!

What this tells us is: from that point (0,-8), you need to go up 1 unit, then over 4, and so forth, until you obtain a line.

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Hope I helped, best wishes & happy studies!

Please reach out to me if any queries arise.

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5 0
1 year ago
Read 2 more answers
An equilateral triangle has a side length of 6. What is the height of the triangle?
vlabodo [156]
Since the height of an equilateral triangle in terms of its side s is s√3/2, the height of the triangle is 6√3/2 = 3√3 and so the area is (1/2)(6)(3√3) = 9√3. 

<span>If we draw a horizontal line a height of h from the base of the triangle, the region is split into two regions: the lower region consisting of a trapezoid of height h and the upper region consisting of a triangle of height 3√3 - h. </span>

<span>Since the upper triangle and the triangle itself are similar triangles, the base and height are proportional. If we let x denote the base of the length of the upper triangle, we have: </span>

<span>(S. of small triangle)/(S. of big triangle) = (Ht. of small triangle)/(Ht. of big triangle) </span>
<span>==> x/6 = (3√3 - h)/(3√3) </span>
<span>==> x = (6√3 - 2h)/√3 </span>

<span>Thus, the area of the upper triangle is: </span>

<span>A = (1/2)[(6√3 - 2h)/√3](3√3 - h) = [(6√3 - 2h)(3√3 - h)]/(2√3). </span>
<span>(Made a dumb mistake about the height here for some reason) </span>

<span>Since we require that the area of this triangle is to be half of the total area (9√3/2), we need to solve: </span>

<span>[(6√3 - 2h)(3√3 - h)]/(2√3) = 9√3/2 </span>
<span>==> (6√3 - 2h)(3√3 - h) = 27 </span>
<span>==> 54 - 6h√3 - 6h√3 + 2h^2 = 27 </span>
<span>==> 2h^2 - 12h√3 + 27 = 0. </span>

<span>Solving with the Quadratic Formula gives: </span>

<span>h = (6√3 + 3√6)/2 ≈ 8.87 units and h = (6√3 - 3√6)/2 ≈ 1.52 units. </span>

<span>Since h = (6√3 + 3√6)/2 would place the line outside of the triangle, we pick h = (6√3 - 3√6)/2. </span>

<span>Therefore, the line should be ==> (6√3 - 3√6)/2 units from the base. </span>

<span>I hope this helps! ^^ Brainliest Please?</span><span>
</span>
5 0
3 years ago
Read 2 more answers
What the answer is for the question
Slav-nsk [51]
The answer would be -144
7 0
2 years ago
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