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docker41 [41]
2 years ago
13

100 POINTS

Mathematics
2 answers:
Naily [24]2 years ago
8 0
  • f(x)=2x^2+3
  • g(x)=x+2

\\ \sf\longmapsto (f.g)(2)=f(2)g(2)

\\ \sf\longmapsto (2x^2+3)(x+2)

\\ \sf\longmapsto (2(2)^2+3)(2+2)

\\ \sf\longmapsto (2(4)+3)(4)

\\ \sf\longmapsto (8+3)(4)

\\ \sf\longmapsto 11(4)

\\ \sf\longmapsto 44

  • Speed×Time=Distance

Option C is correct

Ira Lisetskai [31]2 years ago
4 0

Answer:

D is right

Step-by-step explanation:

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Please go to Lesson 11.11. Please show you're work AND show you're work in paper and take a picture and send it to me. Please he
nasty-shy [4]
Dear SailorMars, since I don't have a phone I will show my work on this chat. For 2. we can do 1x1x28=28 cm³ and 2x2x7=28cm³ which will have a square base, which is 2 possible molds. For 3. we can do 10x1x36=360in³, 10x2x18=360in³, 10x3x12=360in³, 10x4x9=360in³, and 10x6x6=360in³ which will have a dimension of 10 in, which is 5 possible molds.
For 4. multiply 12x8x4=384in³ and multiply 20x15x9=to get 2700in³. With the two measurements, subtract 2700-384=2316in³ of space in the box.
For 5. multiply the equations 5x2x1, 5x2x2, 5x2x3, 5x2x4, and 5x2x5 to get the volumes in order 10ft³, 20ft³, 30ft³, 40ft³, and 50ft³.
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For 1. multiply 6x8x10 to get 480 in³; the answer is C
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3 0
4 years ago
Pls help will give 5 stars and heart
Tamiku [17]
So the circle is 39.25
And the area of triangle 30 together about 39.25
5 0
3 years ago
Regular admission price for a family to enter an amusement park is $345.80. The Patel family used a discount coupon that gave th
mylen [45]
100-35=65
65 over 100 x 345.80
=224.77
345.80-224.77=121.03
3 0
3 years ago
Lollllljlalekfjlksjekjflskjeflksjekfjsekfjskfesefs
MissTica

Answer:

dijkcvrhjdcrhrbfike

Step-by-step explanation:

<3

7 0
3 years ago
Read 2 more answers
Let u = (1, k) and v = (2, 1). Find k such that The distance between u and v is 1 u and v are orthogonal The angle between u and
SVETLANKA909090 [29]

Answer:k=1,k=-2,k=8\pm 5\sqrt{3}

Step-by-step explanation:

Given two vectors

u=1\hat{i}+k\hat{j}

v=2\hat{i}+1\hat{j}

\left ( i\right )Distance between them is given by

|u-v|=\sqrt{\left ( 2-1\right )^2+\left ( 1-k\right )^2}=1

squaring both side

1^{2}+\left ( 1-k\right )^2=1

k^2-2k+1=0

\left ( k-1\right )^2=0

k=1

\left ( ii\right )

angle between u and v is 90 i.e. orthogonal

u\dot v=0

\left ( 1\hat{i}+k\hat{j}\right )\dot \left ( 2\hat{i}+1\hat{j}\right )=0

2+k=0

k=-2

\left ( iii\right )

angle between u & v is \frac{\pi }{3}

u\dot v=|u||v|cos\left (\frac{\pi }{3}\right )

|u|=\sqrt{1^2+k^2}

|v|=\sqrt{2^2+1^2}

2+k=\left ( \sqrt{1+k^2}\right )\left ( \sqrt{5}\right )cos\left ( \frac{\pi }{3}\right )

\left ( 4+2\right )^2=\left ( 1+k^2\right )5

k^2-16k-11=0

k=8\pm 5\sqrt{3}

7 0
3 years ago
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