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Masja [62]
3 years ago
14

Could someone help? I’m confused

Mathematics
1 answer:
andre [41]3 years ago
3 0
He will only need to sell one
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The equation of line A is y = 7x + 12. Line B is perpendicular to line A and passes through the point . What would be the soluti
max2010maxim [7]
Since B is perpendicular to A. We can say that the gradient of B will be -1/7 (product of the gradients of 2 perpendicular lines has to be -1).
Now we know that the equation for B is y=-(1/7)x + c with c being the y intercept.
Since the point isnt specified in the question, we could leave the equation like this.
But if there is a given point that B passes through, just plug in the x and y values into their respective places and solve to find c. That should give you the equation for b.
Now, to find the solution of x, we have 2 equations:
1) y=7x+12
2)y=-(1/7)x+c

In this simultaneous equation we see that y is equal to both the expressions. So,
7x+12=-(1/7)x+c

Now, since the value of c is not found, we cannot actually find the value of x, but if we would find c, we could also find x since it would only be a matter of rearranging the equation.
And there you go, that is your solution :)
3 0
2 years ago
Edit PDF assignments with Kami
madreJ [45]

Answer:

halooooooo hallo hallo hallo hallo hallo hallo hallo hallo hallo hallo hallo hallo hallo

7 0
3 years ago
A penguin can dive 48 meters below the surface of the water to reach a fish. It dives 2% of the total depth every 1 second.
Alenkinab [10]

Answer:

8 becaus it dives. 2 meters second so if it dives to meters every second then all you have to do is add to to 4 seconds

4 0
2 years ago
Determine the intercepts of the line. <br> -5x-4y=10
storchak [24]

Answer:

x-intercept:(-2,0)\\\\y-intercept:(0,-\frac{5}{2})

Step-by-step explanation:

The y-intercept is where x is 0 (0,y)

The x-intercept is where y is 0 (x,0)

Insert 0 as the value for x to find the corresponding y value:

-5(0)-4y=10

Simplify multiplication:

0-4y=10\\\\-4y=10

Isolate the variable. Divide both sides by 4:

\frac{-4y}{4}=\frac{10}{4}  \\\\-y=\frac{10}{4} \\\\-y=\frac{5}{2}

Make the variable positive. Multiply both sides by -1:

-1(-y)=-1(\frac{5}{2})\\\\y=-\frac{5}{2}

The y-intercept is at (0,-\frac{5}{2}).

Insert 0 as the value for y to determine the value of x:

-5x-4(0)=10

Simplify multiplication:

-5x-0=10\\\\-5x=10

Isolate x. Divide both sides by 5:

\frac{-5x}{5} =\frac{10}{5} \\\\-x=2

Multiply both sides by -1:

-1(-x)=-1(2)\\\\x=-2

The x-intercept is at (-2,0).

:Done

8 0
3 years ago
In a survey, 11 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped
pickupchik [31]

Answer:

The population standard deviation is not known.

90% Confidence interval by T₁₀-distribution: (38.3, 53.7).

Step-by-step explanation:

The "standard deviation" of $14 comes from a survey. In other words, the true population standard deviation is not known, and the $14 here is an estimate. Thus, find the confidence interval with the Student t-distribution. The sample size is 11. The degree of freedom is thus 11 - 1 = 10.

Start by finding 1/2 the width of this confidence interval. The confidence level of this interval is 90%. In other words, the area under the bell curve within this interval is 0.90. However, this curve is symmetric. As a result,

  • The area to the left of the lower end of the interval shall be 1/2 \cdot (1 - 0.90)= 0.05.
  • The area to the left of the upper end of the interval shall be 0.05 + 0.90 = 0.95.

Look up the t-score of the upper end on an inverse t-table. Focus on the entry with

  • a degree of freedom of 10, and
  • a cumulative probability of 0.95.

t \approx 1.812.

This value can also be found with technology.

The formula for 1/2 the width of a confidence interval where standard deviation is unknown (only an estimate) is:

\displaystyle t \cdot \frac{s_{n-1}}{\sqrt{n}},

where

  • t is the t-score at the upper end of the interval,
  • s_{n-1} is the unbiased estimate for the standard deviation, and
  • n is the sample size.

For this confidence interval:

  • t \approx 1.812,
  • s_{n-1} = 14, and
  • n = 11.

Hence the width of the 90% confidence interval is

\displaystyle 1.812 \times \frac{14}{\sqrt{10}} \approx 7.65.

The confidence interval is centered at the unbiased estimate of the population mean. The 90% confidence interval will be approximately:

(38.3, 53.7).

5 0
2 years ago
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