X(5-8) would be the answer
Answer:
There are N students in the class.
We know that ONLY ONE of the inequalities is true:
N < 10
N > 10
N < 22
N > 22
We want only one of these four inequalities to be true.
Remember that if we have:
x > y
y is not a solution, because:
y > y is false.
Then:
If we take N = 10, then:
N < 22
Is the only true option.
While if we take N = 22
N > 10
is the only true option.
So there are two possible values of N.
Answer:
first we find the common difference.....do this by subtracting the first term from the second term. (9 - 3 = 6)...so basically, ur adding 6 to every number to find the next number.
we will be using 2 formulas....first, we need to find the 34th term (because we need this term for the sum formula)
an = a1 + (n-1) * d
n = the term we want to find = 34
a1 = first term = 3
d = common difference = 6
now we sub
a34 = 3 + (34-1) * 6
a34 = 3 + (33 * 6)
a34 = 3 + 198
a34 = 201
now we use the sum formula
Sn = (n (a1 + an)) / 2
S34 = (34(3 + 201))/2
s34 = (34(204)) / 2
s34 = 6936/2
s34 = 3468 <=== the sum of the first 34 terms:
So we have the equation:
Then we need to multiply by 4 on both sides to get rid of the denominator on the left:
Then we subtract 9 on both sides to solve for z:
Therefore the answer is z = -0.6.
Answer:
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Step-by-step explanation:
