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Yuliya22 [10]
2 years ago
6

Four emple yees can service 20

Mathematics
1 answer:
photoshop1234 [79]2 years ago
3 0

Answer:

4

Step-by-step explanation:

Given that 20 / 5 = 4

It will take just about 4 hours (240 minutes).

Each car requires 1 hour to wash.

So, it will erase 1 hour.

I hope this helps. ❤

If this is wrong, please let me know.

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A piece of string is 42 meters long. It is cut into three pieces so that one piece is 15 meters longer than the other two, which
Semmy [17]
To start this problem, we know that one of the three pieces that the string is cut into is 15 meters longer than the others. Subtract 15 from 42 to get 27.
Then, from there, you can cut that number (<em>divide</em>) by three to get the length of the two shorter strings. Simply add the 15 meters you didn't use yet to one of the pieces to find the longer string, and you have your lengths.

Hope this helps!
-refrac532
4 0
3 years ago
3x + 2 when x = 5<br> Pls
Kisachek [45]

Answer:

15 + 2 = 17

Step-by-step explanation:

7 0
2 years ago
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When running a 100 meter race Bill reaches his maximum speed when he is 45 meters from the starting line and 5 seconds have elap
Mkey [24]

Bill's speed is constant after 5 seconds and 45 meters into the race.

Correct responses:

a. Bill's maximum speed is 8 m/s

b. 24 meters

c. 57 meters

<h3>Methods used to calculate speed and distance traveled</h3>

Given parameters are;

The distance of the race = 100 meter

Distance at which Bill reaches maximum speed = 45 meters

Speed Bill maintains after 5 seconds = The maximum speed

Time at which Bill is 85 meters from the starting line = 10 seconds after start

a. Required;

Bill's maximum speed in meters.

Solution:

Distance Bill runs at maximum speed, d = 85 m - 45 m = 40 m

Time at which Bill runs the 40 m at maximum speed, <em>t</em> = 10 s - 5 s = 5 s

Speed = \mathbf{\dfrac{Distance}{Time}}

Therefore;

  • Bill's \  maximum \ speed = \dfrac{40 \ m}{5 \ s} = \underline{8 \ m/s}

b. i. Required:

The distance Bill will run for 3 seconds at the maximum speed;

Solution:

Distance,<em> s</em> = Speed, <em>v</em> × Time, <em>t</em>

<em />

The distance traveled at maximum speed in 3 seconds is therefore;

Distance = 8 m/s × 3 s = 24 m

The distance Bill travels in 3 seconds at the maximum speed is 24 meters.

ii) The distance Bill travels at 8 seconds after start, is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 3 seconds = 24 meters

Therefore;

  • Bill's distance from the starting line 8 seconds after start is 45 meters + 25 meters = <u>69 meters</u>

c. Bill's distance 6.5 seconds after the start of the race is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 1.5 seconds = 1.5 s × 8 m/s = 12 meters

  • Bill's distance from the starting line 6.5 seconds after start of the race = 45 meters + 12 meters = <u>57 meters</u>

Learn more about distance, speed, time, relationship here:

https://brainly.in/question/49075584

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WHERE ARE THE EXPERTS AND ACE!!!!!!! I NEED HELP PLS SHARE YO SMARTNESS!!!!! WILL GIVE BRAINLIEST AND RATE AND VOTE!!!
zmey [24]

Answer:

D and C

Step-by-step explanation:

1) You can cross check using desmos.

2) cos(120) is - 0.5

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What is the domain of the function
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5. D (the number under the square root symbol must be greater than or equal to 0. 


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