<span>x^3 - 3(x)^2 + x - 3 < 0
х</span>²(х-3)+(х-3)<0
(x-3)(x²+1)<0
x²+1 always more than zero
therefore (x-3)(x²+1)<0 when x-3<0, x<3
Well u must divide the area by the width this will give you the length, 5.8/2.25=2.5777778 which is around 2 3/5
Answer:
Here is the answer...hope it helps
Answer:
option 2.
the others are simultaneous equations in two unknowns but 7x-2y have the same value and the value can't be two different things at once
<span>v=d/t; t=d/v
let c=rate of the current
6/(4+c)+6/(4-c)=8
(24-6c+24+6c)/(16-c²)=8
48=128 - 8c²; c=√10 miles per hour</span>