Answer:
35.8
Step-by-step explanation:
= 358
We know that our answer can never be greater than 358 since the dividend
is 340.1 and the divisor is 9.5;
Also,
Both values are to one decimal places and we can use this to solve the problem;
9 can divide 340 in about 37 place with a remainder of 7,
So, it is appropriate to make the solution 35.8
Based on the given condition Diego utilized, it can be said that he used multiplication property when he multiplied both sides of the equation by 6 and then substitution property when he substituted 6 to the original equation.
(c) Multiplication property of equality and substitution property of equality
Answer :
<em>3</em><em>5</em><em> </em><em>h</em><em>o</em><em>t</em><em> </em><em>d</em><em>o</em><em>g</em><em>s</em><em> </em><em>a</em><em>n</em><em>d</em><em> </em><em>5</em><em>2</em><em> </em><em>s</em><em>o</em><em>d</em><em>a</em><em>s</em><em> </em><em>w</em><em>e</em><em>r</em><em>e</em><em> </em><em>s</em><em>o</em><em>l</em><em>d</em><em>.</em><em> </em>
Step-by-step explanation:
Let the no. of hot dogs sold be x and no. of sodas sold be y .
Put together your two equations, and find the values of x and y, to know exactly how many hot dogs and sodas were sold.
Hope i was able to help:)))
Answer:
3.84% probability that it has a low birth weight
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

If we randomly select a baby, what is the probability that it has a low birth weight?
This is the pvalue of Z when X = 2500. So



has a pvalue of 0.0384
3.84% probability that it has a low birth weight