All categories

3 years ago

What is a bond and how do you make money from it?

Mathematics

1 answer:

il63 [147K]3 years ago

6 0

Answer:

Bonds are among a number of investments known as fixed-income securities. They are debt obligations, meaning that the investor loans a sum of money (the principal) to a company or a government for a set period of time, and in return receives a series of interest payments (the yield).

Step-by-step explanation:

You might be interested in

Elizabeth had a box of 24 crayons. Her little brother ate 2 of them. She split the remaining crayons between her and her 2 frien

Scorpion4ik [409]

24 - 2 (the 2 that he ate) = 22. 22 ÷ 3 (for her and 2 friends) = 7 1/3.

8 0

3 years ago

Read 2 more answers

Use properties to rewrite the given equation. Which equations have the same solution as 3/5x +2/3 + x = 1/2– 1/5x? Check all tha

vodomira [7]

we have

$\frac{3}{5}x+ \frac{2}{3}+x=\frac{1}{2}-\frac{1}{5}x$

Combine like terms in both sides

$(\frac{3}{5}x+ x)+\frac{2}{3}=\frac{1}{2}-\frac{1}{5}x$

we know that

$(\frac{3}{5}x+ x)=(\frac{3}{5}x+ \frac{5}{5}x)=\frac{8}{5}x$

substitute in the expression above

$\frac{8}{5}x+\frac{2}{3}=\frac{1}{2}-\frac{1}{5}x$ -----> equation A

Multiply equation A by $5*3*2=30$ both sides

$30*(\frac{8}{5}x+\frac{2}{3})=30*(\frac{1}{2}-\frac{1}{5}x)$

$48x+20=15-6x$ ---------> equation B

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$48x+6x=15-20$

$54x=-5$ ---------> equation C

Solve for x

$x=-\frac{5}{54} =-0.09$

We are going to proceed to verify each case to determine the solution.

Case a) $\frac{8}{5}x+\frac{2}{3}=\frac{1}{2}-\frac{1}{5}x$

the case a) is equal to the equation A

the case a) have the same solution that the given equation

Case b) $18x+20+30x=15-6x$

Combine like terms in left side

$(18x+30x)+20=15-6x$

$(48x)+20=15-6x$

the case b) is equal to the equation B

the case b) have the same solution that the given equation

Case c) $18x+20+x=15-6x$

Combine like terms in left side

$(18x+x)+20=15-6x$

$(19x)+20=15-6x$

$19x+6x=15-20\\25x=-5\\x=-0.20$

$-0.20\neq -0.09$

therefore

the case c) not have the same solution that the given equation

Case d) $24x+30x=-5$

Combine like terms in left side

$54x=-5$

the case d) is equal to the equation C

the case d) have the same solution that the given equation

Case e) $12x+30x=-5$

Combine like terms in left side

$42x=-5$

$x=-5/42=-0.12$

$-0.12\neq -0.09$

therefore

the case e) not have the same solution that the given equation

therefore

the answer is

case a) $\frac{8}{5}x+\frac{2}{3}=\frac{1}{2}-\frac{1}{5}x$

case b) $18x+20+30x=15-6x$

case d) $24x+30x=-5$

7 0

4 years ago

Read 2 more answers

A box has length 5 feet, width 6 feet, and height 3 inches. Find the volume of the box in cubic feet and in cubic inches.

denpristay [2]

Answer:

90 inches

Step-by-step explanation:

The formula for volume is LxWxH so you just gotta do 5x6x3

which is 90.

7 0

3 years ago

How do you put 3y+x=12 in y=mx+b form

dezoksy [38]

3y+x=12 in slope intercept form is y=-1/3+4

5 0

3 years ago

Read 2 more answers

A professor wants to know whether or not there is a difference in comprehension of a lab assignment among students depending on

san4es73 [151]

Answer:

It is concluded that no difference exists in the comprehension of the lab based on the test scores.

Step-by-step explanation:

Let the populations be normally distributed with a populations standard deviation of 5.32 points for both the text and visual illustrations.

The above statement tells us that the independent t or two sample t test will be performed as both have equal variances and are normally distributed.

This can be easily done through excel.

The following table is obtained

t-Test: Two-Sample Assuming Equal Variances

Text Visual Illustrations

Mean 70.28 75.08

Variance 304.48 228.58

Observations 15 15

Pooled Variance Sp²= 266.53

Pooled Standard Deviation = Sp = 16.33

Hypothesized Mean Difference = x1`-x2`= 0

df = n1+n2-2= 15+15-2= 30-2= 28

t Stat -0.805188239

P(T<=t) two-tail 0.427495979

t Critical two-tail 1.701130908

Let the null and alternate hypotheses be

H0 : u1-u2= 0 against the claim Ha: u1-u2≠0

There is no difference between the means

against the claim

that there is a difference in means of a lab assignment among students depending on if the instructions are given all in text, or if they are given primarily with visual illustrations.

The significance level is ∝= 0.1

The d.f is n1+n2-2= 15+15-2= 30-2=28

This is a two tailed test and the critical region is t (0.025) (28) ≥ 1.7011 and t (0.025) (28) ≤ - 1.7011.

The test statistic is

t= x1-x2/ Sp √1/n1+ 1/n2

t= 70.28 -75.08/ 16.33√1/15 +1/15

t= -4.8/5.963

t= -0.8049811 ( minute difference from excel result due to rounding)

Since the calculated value of t= -0.8049 does not fall in the critical region we conclude that there is no difference in means of a lab assignment among students depending on if the instructions are given all in text, or if they are given primarily with visual illustrations.

We accept the null hypothesis.

The p- value is 0.427495979.

8 0

3 years ago