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4 years ago

What is 2 to the 50th power

2 answers:

8 0

Answer:
1125899906842624 or 1.1258999068×10¹⁵.

Explanation:
To find the answer you will most likely use a calculator and type in 2⁵⁰ or multiply 2 by 2 fifty times, the first method is the most efficient.

White raven [17]4 years ago

3 0

The correct answer is 1,125,899,906,842,624. However most calculators will give this to you in scientific notation, which would be 1.125899907 x 10^15.

This answer is found by multiplying 2 by 2, then multiplying the answer by 2 another 48 times.

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What is greater 9000 meters or 20 kilometers

Alex787 [66]

Answer:

20 kilometers is the answers

6 0

4 years ago

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Formula for circumference

Licemer1 [7]

Answer:

pi x diameter

Step-by-step explanation:

To calculate the circumference of a circle, simply multiply pi (3.14) by the diameter (straight line passing from side to side through the center of the circle)

For instance, if you knew the diameter of a circle was 6 inches. Simply multiply 6 inches by pi!

6 x pi = ?

? approximately equals 18.85 inches.

The circumference of the circle would be 18.85 inches!

If you only have the radius of the circle, simply multiply it by two to get your diameter. Remember, the radius is just half the length of the diameter.

Hope this helps! :)

5 0

3 years ago

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For what point on the curve of y=8x^2 - 3x is the slope of a tangent line equal to -67

AleksandrR [38]

The point on the curve is (–4, 140)

Solution:

Given $y=8x^2-3x$ and slope is –67.

slope = –67

$\frac{dy}{dx}=-67$ – – – – (1)

Now calculate $\frac{dy}{dx}$ for the given curve $y=8x^2-3x$ .

Using differential rule:

$$\frac{d}{dx}(x^n)=nx^{n-1}$

$$\frac{dy}{dx}=\frac{d}{dx}(8x^2-3x)$

$$=\frac{d}{dx}(8x^2)-\frac{d}{dx}(3x)$

$$=(8\times2x^{2-1})-(3\times1x^{1-1})$

$$=16x^1-3x^0$

$$=16x-3$

$$\frac{dy}{dx}=16x-3$ – – – – (2)

Equate (1) and (2).

$16x-3=-67$

$16x=-67+3$

$16x=-64$

⇒ x = –4

Substitute x = –4 in y.

⇒ $y=8(-4)^2-3(-4)$

⇒ $=8(16)+12$

⇒ y = 140

Hence, the point on the curve given is (–4, 140).

3 0

4 years ago

<img src="https://tex.z-dn.net/?f=y%27%3D%20%5Cfrac%7B1%7D%7B6%7D%20x%281-%20y%5E%7B2%7D%20%29" id="TexFormula1" title="y'= \fra

svetlana [45]

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac16x(1-y^2)$
$\displaystyle\int\frac{\mathrm dy}{1-y^2}=\frac16\int x\,\mathrm dx$
$\dfrac12\ln|1+y|-\dfrac12\ln|1-y|=\dfrac1{12}x^2+C$
$\ln\left|\dfrac{1+y}{1-y}\right|=\dfrac16x^2+C$
$\dfrac{1+y}{1-y}=e^{x^2/6+C}$
$-1+\dfrac2{1-y}=Ce^{x^2/6}$
$y=1-\dfrac2{1+Ce^{x^2/6}}$

Given that $y(0)=7$ , we get

$7=1-\dfrac2{1+Ce^0}\implies C=-\dfrac43$

so the particular solution is

$y=1-\dfrac2{1-\frac43e^{x^2/6}}$

8 0

4 years ago

Question 3 of 10 Solve |x + 5|= 7.

damaskus [11]

Answer:

|x + 5|= 7

-7<(x+5)<7

-7<x+5<7

-7-5<x+5-5<7-5

-12 < x <2

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers