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2 years ago

Write y+1=5/2(x-2)+2 in standard form step by step please

1 answer:

6 0

Answer: 5x - 2y = 8

y+1=5/2(x-2)+2

multiply the each side by 2 to get rid of the fraction

2 (y+1) = (5/2 (x-2) +2 )2

2y+2=5(x-2)+4

now distribute the 5

2y+2=5x-10+4

subtract the two from each side

2y=5x-10+4-2

add like terms

2y=5x-8

subtract 5x from each side

2y-5x=-8

multiple the whole equation by -1 to make the 5x a positive

-2y+5x=8

hope this helps!

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Tina must select and answer in any order three of seven

Leno4ka [110]

Answer:

Tina can select and answer the essay questions on her test in 35 ways.

Step-by-step explanation:

The order in which she chooses the questions is not important. For example, choosing questions 1, 3 and 7 is the same as choosing 7, 3 and 1. So we use the combinations formula to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Three questions from a set of 7. So

$C_{7,3} = \frac{7!}{3!(7-4)!} = 35$

Tina can select and answer the essay questions on her test in 35 ways.

6 0

3 years ago

Round 314550 to 1 significant figure

Sauron [17]

300000 all you had to do was round the number down after the 1 significant figure

you round down with
1,2,3,4

and round up with
5,6,7,8,9

so if it asked for 78453
to 2 significant figures you count the numbers and round after that
so 78|453 and since 4 is the next number and it is less that 5 we round down which means it becomes 78000 with is lower than 78453

but if we had 0.0247
and it asked for this number to 2 significant figures all you need to do is count the SIGNIFICANT figures significant means anything with value so that is 1,2,3,4,5,6,7,8,9,10.... 0 has no value therefore we ignore 0 and start counting at the first figure larger than 0
if we go back to 0.0247 that would be the 2 so 2 significant figure of 0.0247 would equal
0.024|7
7 is larger than 5 so we round up to
0.025
tadaa i hope that helped

8 0

3 years ago

Read 2 more answers

Please help! <br><br> explain and correct the error in this calculation

avanturin [10]

2/5/3/8= 56 djnefiiwnd

7 0

3 years ago

Read 2 more answers

Another easy one

andreyandreev [35.5K]

The limit is equivalent to the value of the derivative of $\cos x$ at $x=\dfrac\pi2$ . (See definition of derivative)

$(\cos x)'=-\sin x\implies (\cos x)'\bigg|_{x=\pi/2}=-\sin\dfrac\pi2=-1$

4 0

3 years ago

The College Boards, which are administered each year to many thousands of high school students, are scored so as to yield a mean

Marysya12 [62]

Answer:

a) 15.87% of the scores are expected to be greater than 600.

b) 2.28% of the scores are expected to be greater than 700.

c) 30.85% of the scores are expected to be less than 450.

d) 53.28% of the scores are expected to be between 450 and 600.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 500, \sigma = 100$

a. Greater than 600

This is 1 subtracted by the pvalue of Z when X = 600. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{600 - 500}{100}$

$Z = 1$

$Z = 1$ has a pvalue of 0.8413.

1 - 0.8413 = 0.1587

15.87% of the scores are expected to be greater than 600.

b. Greater than 700

This is 1 subtracted by the pvalue of Z when X = 700. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{700 - 500}{100}$

$Z = 2$

$Z = 2$ has a pvalue of 0.9772

1 - 0.9772 = 0.0228

2.28% of the scores are expected to be greater than 700.

c. Less than 450

Pvalue of Z when X = 450. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{450 - 500}{100}$

$Z = -0.5$

$Z = -0.5$ has a pvalue of 0.3085.

30.85% of the scores are expected to be less than 450.

d. Between 450 and 600

pvalue of Z when X = 600 subtracted by the pvalue of Z when X = 450. So

X = 600

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{600 - 500}{100}$

$Z = 1$

$Z = 1$ has a pvalue of 0.8413.

X = 450

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{450 - 500}{100}$

$Z = -0.5$

$Z = -0.5$ has a pvalue of 0.3085.

0.8413 - 0.3085 = 0.5328

53.28% of the scores are expected to be between 450 and 600.

6 0

3 years ago