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Alex17521 [72]
3 years ago
15

8. The average age of 3 boys is 15 yrs. But if one is not considered,

Mathematics
2 answers:
Vitek1552 [10]3 years ago
8 0

Answer:

Step-by-step explanation:

15 plus 15 plus 15 is 45 - 15 =30

Vera_Pavlovna [14]3 years ago
3 0

5 is the age of the expelled one because 20+20=40/2=20 20+20+5=45/3=15

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The endpoints of a line segment are at the coordinates (–6, 3, 4) and (4, –1, 2). What is the midpoint of the segment?
natulia [17]

Answer:

( - 1,1,3 )

Step-by-step explanation:

Use the midpoint formula:

(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}, \frac{z_1+z_2}{2} )

We want to find the midpoint of the line

that has endpoints.

(\frac{ - 6+4}{2},\frac{3+ - 1}{2}, \frac{4+2}{2} )

We simplify to get;

(\frac{ - 2}{2},\frac{2}{2}, \frac{6}{2} )

This finally gives:

( - 1,1,3 )

The correct answer is A.

7 0
3 years ago
How do you solve 2/5 (c+8.5) =18
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4 0
3 years ago
Which of the following statements about check-cashing companies is FALSE?
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6 0
2 years ago
A normally distributed random variable with mean 4.5 and standard deviation 7.6 is sampled to get two independent values, X1 and
mr Goodwill [35]

Answer:

Bias for the estimator = -0.56

Mean Square Error for the estimator = 6.6311

Step-by-step explanation:

Given - A normally distributed random variable with mean 4.5 and standard deviation 7.6 is sampled to get two independent values, X1 and X2. The mean is estimated using the formula (3X1 + 4X2)/8.

To find - Determine the bias and the mean squared error for this estimator of the mean.

Proof -

Let us denote

X be a random variable such that X ~ N(mean = 4.5, SD = 7.6)

Now,

An estimate of mean, μ is suggested as

\mu = \frac{3X_{1} + 4X_{2}  }{8}

Now

Bias for the estimator = E(μ bar) - μ

                                    = E( \frac{3X_{1} + 4X_{2}  }{8}) - 4.5

                                    = \frac{3E(X_{1}) + 4E(X_{2})}{8} - 4.5

                                    = \frac{3(4.5) + 4(4.5)}{8} - 4.5

                                    = \frac{13.5 + 18}{8} - 4.5

                                    = \frac{31.5}{8} - 4.5

                                    = 3.9375 - 4.5

                                    = - 0.5625 ≈ -0.56

∴ we get

Bias for the estimator = -0.56

Now,

Mean Square Error for the estimator = E[(μ bar - μ)²]

                                                             = Var(μ bar) + [Bias(μ bar, μ)]²

                                                             = Var( \frac{3X_{1} + 4X_{2}  }{8}) + 0.3136

                                                             = \frac{1}{64} Var( {3X_{1} + 4X_{2}  }) + 0.3136

                                                             = \frac{1}{64} ( [{3Var(X_{1}) + 4Var(X_{2})]  }) + 0.3136

                                                             = \frac{1}{64} [{3(57.76) + 4(57.76)}]  } + 0.3136

                                                             = \frac{1}{64} [7(57.76)}]  } + 0.3136

                                                             = \frac{1}{64} [404.32]  } + 0.3136

                                                             = 6.3175 + 0.3136

                                                              = 6.6311

∴ we get

Mean Square Error for the estimator = 6.6311

6 0
3 years ago
If 4c-2=c then 12c= what ??
Nikolay [14]

Answer:

Maybe 0.6

Step-by-step explanation:

4 0
3 years ago
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