So we know that there are 8 slices per large pizza (7), so a total of 56 slices
we would set up a proportion
5/8=x/56
8 times 7 gives you 56, and we would do that same thing to the 5 (multiply it by 7) to get 35?
so now we know that 35 out of 56 slices were eaten
56-35 is 21
so there are 21 slices left over
Answer:
Width = 2x²
Length = 7x² + 3
Step-by-step explanation:
∵ The area of a rectangle is 
∵ Its width is the greatest common monomial factor of 
and 6x²
- Let us find the greatest common factor of 14 , 6 and 
, x²
∵ The factors of 14 are 1, 2, 7, 14
∵ The factors of 6 are 1, 2, 3, 6
∵ The common factors of 14 and 6 are 1, 2
∵ The greatest one is 2
∴ The greatest common factor of 14 and 6 is 2
- The greatest common factor of monomials is the variable with
the smallest power
∴ The greatest common factor of and x² is x²
∴ The greatest common monomial factor of and 6x² is 2x²
∴ The width of the rectangle is 2x²
To find the length divide the area by the width
∵ The area =
∵ The width = 2x²
∴ The length = ( ) ÷ (2x²)
∵ ÷ 2x² = 7x²
∵ 6x² ÷ 2x² = 3
∴ ( ) ÷ (2x²) = 7x² + 3
∴ The length of the rectangle is 7x² + 3
Y^2+5y+10
To 2 Squared go together the regular y go together and then normal go together
Answer:
For the code we have 3 selections.
The first selection is a digit that must be odd, so the options are {1, 3, 5, 7 ,9}
So we have 5 options.
The second selection is a letter from the set of all the letters (27) minus the set of the vowels (5)
So here we have 27 - 5 = 22 options
The third selection is also a letter from the previous set, but because each letter can be used only one time, and in the previous selection we already selected one of the letters, in this selection we have a letter less than in the previous selection.
Here we have 22 - 1 = 21 options.
The total number of combinations (of possible codes) is equal to the product of the number of options for each selection:
C = 5*22*21 = 2310.
There are 2310 different possible codes
