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2 years ago

Please find the value of A and B

Mathematics

2 answers:

lesya [120]2 years ago

4 0

Here's a photo of the solution. Hope this helps and please give brainlist!

4vir4ik [10]2 years ago

3 0

Answer:

For B :

${ \sf{b \degree + 76\degree + 90\degree = 180\degree}} \\ \{angles \: of \: a \: triangle \} \\ b\degree + 166\degree = 180\degree \\ b = 180\degree - 166\degree \\ { \boxed{ \boxed{b = 14\degree}}}$

For A :

$a\degree + b\degree = 180\degree \\ \{angles \: on \: a \: straight \: line \} \\$

but b is 14:

$a + 14 = 180 \\ { \boxed{ \boxed{a = 166\degree}}}$

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tankabanditka [31]

Answer:

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Step-by-step explanation:

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3 years ago

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Vladimir79 [104]

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3 years ago

The dye dilution method is used to measure cardiac output with 3 mg of dye. The dye concentrations, in mg/L, are modeled by c(t)

Lemur [1.5K]

Answer:

Cardiac output: $F=0.055 L\s$

Step-by-step explanation:

Given : The dye dilution method is used to measure cardiac output with 3 mg of dye.

To Find : Find the cardiac output.

Solution:

Formula of cardiac output: $F=\frac{A}{\int\limits^T_0 {c(t)} \, dt}$ ---1

A = 3 mg

$\int\limits^T_0 {c(t)} \, dt =\int\limits^{10}_0 {20te^{-0.06t}} \, dt$

Do, integration by parts

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[20t\int{e^{-0.6t} \,dt}-\int[\frac{d[20t]}{dt}\int {e^{-0.6t} \, dt]dt]^{10}_0$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20}{0.6}\int {e^{-0.6t} \,dt]^{10}_0$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20e^{-0.6t}}{(0.6)^2}]^{10}_{0}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-200e^{-6}}{0.6}+\frac{20e^{-6}}{(0.6)^2}]+\frac{20}{(0.60^2}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=\frac{20(1-e^{-6}}{(0.6)^2}-\frac{200e^{-6}}{0.6}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0\sim {54.49}$

Substitute the value in 1

Cardiac output: $F=\frac{3}{54.49}$

Cardiac output: $F=0.055 L\s$

Hence Cardiac output: $F=0.055 L\s$

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2 years ago

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Answer:

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Step-by-step explanation:

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BartSMP [9]

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3 years ago

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Please find the value of A and B​

Please find the value of A and B