The congruence theorem is always the same
Answer:
y = 1/3x - 2
Step-by-step explanation:
We are asked to find the equation of a line with two points
Step1: find the slope
m = (y_2 - y_1)/(x_2 - x_1)
( 0 , -2) (6 , 0)
x_1 = 0
y_1 = -2
x_2 = 6
y_2 = 0
Insert the values
m = ( 0 - (-2)/ (6 - 0)
m = ( 0 + 2)/(6 - 0)
m = 2/6
m = (2/2)/(6/2)
m = 1/3
Step 2 : substitute m into the equation of line
y = mx + c
y = intercept y
m = slope
x = intercept x
c = intercept
y = 1/3x + c
Step 3: sub any of the two points
Let's pick ( 6 ,0)
x = 6
y = 0
Insert the values into
y = 1/3x + c
0 = 1/3(6) + c
0 = 1*6/3 + c
0 = 6/3 + c
0 = 2 + c
c = 0 - 2
c = -2
Sub c = -2
y = 1/3x - 2
The equation of the line is
y = 1/3x - 2
Answer:
x²+1/x² = 51
Explanation:
Given x - 1/x = 7 ---(1)
We know the algebraic identity:
a²+b²-2ab = (a-b)²
Or
a²+b² = (a-b)²+2ab
Now,
x²+1/x²
= (x-1/x)²+2*x*(1/x)
= (x-1/x)²+2
:7²+2 [ from (1)] =
= 49+2
= 51
Therefore,
x²+1/x² = 51
Answer:
It's C
Step-by-step explanation:
I just took the test
