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3 years ago

Which of the following are accurate descriptions of the distribution below?

Mathematics

2 answers:

ivanzaharov [21]3 years ago

8 0

Answer:

both option (A) & (B) is description of given distribution.

Step-by-step explanation:

The outlier is a point which lies differently or far away from rest points in datasets or distribution.

Here we can self-time for one apple on the 10th day is outlier present in the distribution. Thus Option (A) is correct.

We divide the heterogeneous group into many homogeneous groups, these homogeneous group is known as Cluster. It can be seen naturally.

Also, here distribution is divided into many clusters and we can see given distribution has many clusters and one of them is from 4 to 6 days. Thus Option (B) is also a correct option here.

mart [117]3 years ago

5 0

The single apple on day 10 is an outlier because it is all by its self and the there is a cluster from 4 to 6 because there are multiple apples on days 4, 5, and 6 so your answers would be A and B :)

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A batch consists of 12 defective coils and 88 good ones. Find the probability of getting two good coils when two coils are rando

Allushta [10]

Answer:

The probability of getting two good coils when two coils are randomly selected if the first selection is replaced before the second is made is 0.7744

Solution:

Total number of coils = number of good coils + defective coils = 88 + 12 = 100

p(getting two good coils for two selection) = p( getting 2 good coils for first selection ) $\times$ p(getting 2 good coils for second selection)

p(first selection) = p(second selection) = $\frac{\text { number of good coils }}{\text { total number of coils }}$

Hence, p(getting 2 good coil for two selection) = $\frac{88}{100} \times \frac{88}{100} =\bold{0.7744}$

5 0

3 years ago

Harold has 4 classes each morning. Each class is 1 hour long, and there are 10 minutes between classes. The first class is at 8

Viktor [21]

The fourth class ends at 12:30 pm

Solution:

Given that Harold has 4 classes each morning

Each class is 1 hour long, and there are 10 minutes between classes

The first class is at 8 A.M

To find: Time at which fourth class ends

Since each is 1 hour long and 10 minutes gap between classes

First class = 8 A.M to 9 A.M

Second class = 9:10 A.M to 10 : 10 AM

Third class = 10 : 20 AM to 11 : 20 AM

Fourth class = 11 : 30 AM to 12 : 30 PM

Thus the fourth class ends at 12:30 pm

4 0

3 years ago

Pls answer the question attached

barxatty [35]

$\huge\mathfrak{\underline{answer:}}$

$\large\bf{\angle ACD = 105°}$

__________________________________________

$\large\bf{\underline{Here:}}$

BCD is an isosceles right triangle , right angled at D
ABC is an equilateral triangle

$\large\bf{\underline{To\:find:}}$

∠ ACD

$\large\bf{In\: triangle\:ABC:}$

❒ Sum of all angles is 180° , since it is an equilateral triangle all the three angles would be same

$\large\bf{\underline{So}}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\bf{⟼\angle ACB = \frac{180}{3}}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\bf{⟼\angle ACB = 60°}$

$\large\bf{In\: triangle\:BDC}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\bf{⟼\angle D = 90°}$

$\bf{⟼\angle DBC =\angle DCB }$ (Isosceles triangle)

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\bf{⟼\angle DBC + \angle BDC + \angle DCB = 180° }$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\bf{⟼2\angle DCB + 90° = 180°}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\bf{⟼2\angle DCB = 180 -90}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\bf{⟼\angle DCB = \frac{90}{2}}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\bf{⟼\angle DCB = 45°}$

$\large\bf{\underline{Therefore,}}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\bf{⟹\angle ACD = \angle ACB + \angle DCB}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\bf{⟹\angle ACD = 60+45}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\large\bf{⟹\angle ACD = 105°}$

6 0

3 years ago

You jog 2 kilometers in 12 minutes. Your friend jogs 3 kilometers in 16.5 minutes. Who jogs faster? You jog faster. Your friend

Darya [45]

Answer:

a) Who jogs faster?

Your friend jogs faster because he jogs with a speed of 10.91 km/hr

Step-by-step explanation:

Speed = Distance(km)/Time(hours)

Question 2 How much sooner will the faster jogger finish a five-kilometer race?

Your friend's will finish a 5km race at a speed of 18.18 km/hr

Your speed is :

You jog 2 kilometers in 12 minutes.

Convert 12 minutes to hours

60 minutes = 1 hour

12 minutes = x

x = 12/60

x = 1/5 hour

Your speed is calculated as:

2km/1/5hour

= 2 km ÷ 1/5 hour

= 2 × 5

= 10 km/hr

Your friend's speed is calculated as:

Your friend jogs 3 kilometers in 16.5 minutes.

Convert 16.5 minutes to hours

60 minutes = 1 hour

16.5 minutes = x

x = 16.5/60

x = 0.275 hour

Your speed is calculated as:

3km/0.275 hour

= 10.909090909 km/hr

Approximately = 10.91km/hr

a) Who jogs faster?

Your friend jogs faster because he jogs with a speed of 10.91 km/hr

Question 2 How much sooner will the faster jogger finish a five-kilometer race?

Your friend jogs faster, hence:

3 km = 10.91 km/hr

5km = x

x = 5 × 10.91/3

x = 18.183333333 km/hr

Your friend's will finish a 5km race at a speed of 18.18 km/hr

4 0

3 years ago

Write an equation using this points -2,2,-2

Korvikt [17]

Answer:

2+-2+-2=-2

Step-by-step explanation:

8 0

4 years ago