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Answer:
The time elapsed is 0.017224 s
Solution:
As per the question:
Analog signal to digital bit stream conversion by Host A =64 kbps
Byte packets obtained by Host A = 56 bytes
Rate of transmission = 2 Mbps
Propagation delay = 10 ms = 0.01 s
Now,
Considering the packets' first bit, as its transmission is only after the generation of all the bits in the packet.
Time taken to generate and convert all the bits into digital signal is given by;
t =
t = (Since, 1 byte = 8 bits)
t = 7 ms = 0.007 s
Time Required for transmission of the packet, t':
Now, the time elapse between the bit creation and its decoding is given by:
t + t' + propagation delay= 0.007 + + 0.01= 0.017224 s
Answer:
A.) in order traversal - 9 32 35 14 27 25 2 7 29
B.) pre-order traversal - 25 14 32 9 35 27 7 2 29
C.) post-order traversal - 9 35 32 27 14 2 29 25
Explanation:
Given - 25, 14, 7, 32, 27, 2, 29,9,35
To find - On a separate electronic page or sheet of paper:
1. List the values using in order traversal
2. List the values using pre-order traversal
3. List the values using post-order traversal
Proof -
Given values are -
25, 14, 7, 32, 27, 2, 29,9,35
1.)
In order is -
9 32 35 14 27 25 2 7 29
2.)
Pre-order is - (Root left right)
List nodes of first time visit
25 14 32 9 35 27 7 2 29
3.)
Post-order is - (Left Right Root)
List nodes of third time visit
9 35 32 27 14 2 29 25
