Answer:
When an instruction is sent to the CPU in a binary pattern, how does the CPU know what instruction the pattern means
Explanation:
When the CPU executes the instructions, it interprets the opcode part of the instruction into individual microprograms, containing their microcode equivalents. Just so you know, a full assembly instruction consists of an opcode and any applicable data that goes with it, if required (register names, memory addresses).
The assembly instructions are assembled (turned into their binary equivalent 0s and 1s, or from now on, logic signals). These logic signals are in-turn interpreted by the CPU, and turned into more low-level logic signals which direct the flow of the CPU to execute the particular instruction.
Answer:
if(revenue.cents - expenses.cents < 0){
profit.dollars = revenue.dollars - expenses.dollars - 1;
profit.cents = 1 - revenue.cents - expenses.cents;
}
else{
profit.dollars = revenue.dollars - expenses.dollars;
profit.cents = revenue.cents - expenses.cents;
}
Explanation:
We know that profit is given as: revenue - expenses from the question.
From the given expression above;
if(revenue.cents - expenses.cents < 0)
then profit.dollar will be revenue.dollars - expenses.dollars - 1; the 1 is to be carry over to the cent part. And the profit.cent will be 1 - revenue.cents - expenses.cents;
else the profit.dollars and the profit.cent is computed directly without needing to carry over:
profit.dollars = revenue.dollars - expenses.dollars;
profit.cents = revenue.cents - expenses.cents;
Answer:
N=5 key task decision start and end
Explanation:
Larry page is the correct answer :)