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3 years ago

PLEASE HELP WITH THIS ONE QUESTION

Mathematics

1 answer:

Nana76 [90]3 years ago

3 0

Answer:

I'm not sure about the factors, but it's reflected over the x axis if they helps narrow it down

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over the summer steven"s tutor told him he needed to complete 15 total workbook pages. he finished 5 workbook pages the first we

Eduardwww [97]

He has 2/3 left to complete.
He did 5 out of 15 which is 5/15 or 1/3. Therefore he has 1-1/3 or 2/3 left.

7 0

3 years ago

Solve ln 2 + ln x = 5. Round to the nearest thousandth, if possible.

azamat

Answer:

The value of x nearest to thousandths is, 74.207

Step-by-step explanation:

Solve : $\ln 2 + \ln x = 5$

$\ln$ represents the logarithmic function with base e.

Using logarithmic properties:

$\ln (mn) = \ln m + \ln n$

$\ln x = a$ , then $x = e^a$

$\ln 2 + \ln x = 5$

Apply the logarithmic properties; we have

$\ln 2x = 5$

then;

$2x = e^5$

$2x=148.41315910258$

Divide both sides by 2 we get;

$x = 74.2065796$

Therefore, the value of x nearest to thousandths is, 74.207

3 0

3 years ago

Two children own two-way radios that have a maximum range of 3 miles. One leaves a certain point at 1:00 P.M., walking due north

Grace [21]

Answer:

The answer is 21 minutes

Step-by-step explanation:

We use the equation Xf = Xo + vt

1) At 1:00 PM, child one leaves the starting point heading north at a constant velocity of 6 mi/hr or .1 [mi/min] (divide by 60 to convert from [mi/hr] to [mi/min])

2) He walks for 15 minutes before kid 2 starts walking. In 15 minutes he is able to cover 1.5 [mi]

$x_{1f1} =x_{o} +v_{1} t_{1} \\x_{1f1} =0+.1(15)\\x_{1f1} =1.5 [mi]$

3) Now, child 2 starts walking and we know that when the range reaches 3 miles, they won´t be able to communicate. So the sum of the final position of child 1 and child 2 must be 3[mi]