common difference, d = -3
f1 = -13
An arithmetic sequence f(n) = f1 + d(n - 1)
so f(n) = -13 - 3(n - 1)
f(46) = -13 - 3(46-1) = -13 -3(45) = -13 - 135 = -148
Answer:
f(46) = - 148
Answer:
x² - 10x + 21
Explanation:
To answer this question, we will simply multiply each term from the first bracket by each term from the second and then combine like terms to get the final expression.
This can be done as follows:
(x - 3)(x - 7)
x(x) + x(-7) -3(x) -3(-7)
x² - 7x - 3x + 21
x² - 10x + 21
Hope this helps :)
Answer:
For x = 10:

For y = - 3:

Step-by-step Explanation:
Before we start let's recall the formula for the linear equations.

So first let's solve for x=10:

Move 10 to the other side.

As there is no y given we will simply write 0y.

Now let's solve for y=-3:

Move -3 to the other side.

As there is no x given we will simply write 0x.

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Answer:

Step-by-step explanation:
Step 1: Define
Difference Quotient: 
f(x) = -x² - 3x + 1
f(x + h) means that x = (x + h)
f(x) is just the normal function
Step 2: Find difference quotient
- <u>Substitute:</u>
![\frac{[-(x+h)^2-3(x+h)+1]-(-x^2-3x+1)}{h}](https://tex.z-dn.net/?f=%5Cfrac%7B%5B-%28x%2Bh%29%5E2-3%28x%2Bh%29%2B1%5D-%28-x%5E2-3x%2B1%29%7D%7Bh%7D)
- <u>Expand and Distribute:</u>
![\frac{[-(x^2+2hx+h^2)-3x-3h+1]+x^2+3x-1}{h}](https://tex.z-dn.net/?f=%5Cfrac%7B%5B-%28x%5E2%2B2hx%2Bh%5E2%29-3x-3h%2B1%5D%2Bx%5E2%2B3x-1%7D%7Bh%7D)
- <u>Distribute:</u>

- <u>Combine like terms:</u>

- <u>Factor out </u><em><u>h</u></em><u>:</u>

- <u>Simplify:</u>

Answer:
x=4
Step-by-step explanation:
It's a parallel line so the equation is
100+19x+4=180
19x=180-100-4
19x=76
x=76/19
x=4