Can someone help me out here?

Help!!!!!!!!!!!!!!!!!!!!!!!!!!!! asap!!!!!!!!!!! 50 pts and brainliest!

Stels [109]

Answer:

-5/4

Step-by-step explanation:

Pick two points on the line

(-4,0) and (0,-5)

We can use the slope formula

m = (y2-y1)/(x2-x1)

= ( -5 -0)/(0 - -4)

= (-5-0)/(0+4)

= -5/4

6 0

3 years ago

A raised garden is a rectangular prism with a width of 60 in. And a length that is three times the height "h". The volume of the

kati45 [8]

Answer:

24 in

Step-by-step explanation:

From the question,

The formula for finding the volume of a rectangular prism is

V = l×w×h...................... Equation 1

Where l = length, w = width, h = height.

From the question, we were told that the length of the prism is three times the height.

i.e,

l = 3h....................... Equation 2

Substitute equation 2 into equation 1

V = 3h×w×h

V = 3h²w............... Equation 3

Given: V = 103680 in³, w = 60 in

Substitute these values into equation 3 and solve for h

103680 = 3(h²)(60)

103680 = 180h²

h² = 103680/180

h² = 576

h = $\sqrt{576}$

h = 24 in.

Hence the height of the raised garden is 24 in

6 0

3 years ago

The ages of a random sample of five university professors are 39, 54, 61, 72, and 59. Using this information, find a 99% confide

kondor19780726 [428]

Answer:

99% confidence interval for the population standard deviation = (74.97 , 635.20).

Step-by-step explanation:

We are given that the ages of a random sample of five university professors are 39, 54, 61, 72 and 59. Also, it is provided that the ages of university professors are normally distributed.

So, firstly the pivotal quantity for 99% confidence interval for the population standard deviation is given by;

P.Q. = $\frac{(n-1)s^{2} }{\sigma^{2} }$ ~ $\chi^{2} __n_-_1$

where, s = sample standard deviation

$\sigma$ = population standard deviation

n = sample of university professors = 5

Also, $s^{2}$ = $\frac{\sum (X-\bar X)^{2} }{n-1}$ = 144.5

So, 99% confidence interval for population standard deviation, $\sigma$ is;

P(0.2070 < $\chi^{2} __5_-_1$ < 14.86) = 0.99 {As the table of $\chi^{2}$ at 4 degree of freedom

gives critical values of 0.2070 & 14.86}

P(0.2070 < $\frac{(n-1)s^{2} }{\sigma^{2} }$ < 14.86) = 0.99

P( $\frac{ 0.2070}{(n-1)s^{2} }$ < $\frac{1 }{\sigma^{2} }$ < $\frac{ 14.86}{(n-1)s^{2} }$ ) = 0.99

P( $\frac{ (n-1)s^{2}}{14.86 }$ < $\sigma^{2}$ < $\frac{ (n-1)s^{2}}{0.2070 }$ ) = 0.99

99% confidence interval for $\sigma^{2}$ = ( $\frac{ (n-1)s^{2}}{14.86 }$ , $\frac{ (n-1)s^{2}}{0.2070 }$ )

= ( $\frac{ (5-1) \times 144.5^{2}}{14.86 }$ , $\frac{ (5-1) \times 144.5^{2}}{0.2070 }$ )

= (5620.525 , 403483.092)

99% confidence interval for $\sigma$ = ( $\sqrt{5620.525}$ , $\sqrt{403483.092}$ )

= (74.97 , 635.20)

Therefore, 99% confidence interval for the population standard deviation of the ages of all professors at the university is (74.97 , 635.20).

8 0

4 years ago

A rectangular prism with the volume of 10 cubic units is filled with cubes with side links of 1/2 unit how many 1/2 unit kids do

ELEN [110]

Answer 80
Required cubes 10/1/8=80

8 0

4 years ago

Antonio is building a 1:240 scale model of a real castle. His model has a rectangular base that is 2.5 feet wide and 2 feet long

34kurt

The right approach to this problem is to first determine the real dimension by using the given scale factor.
width : (2.5 ft) x 250 = 625 ft
length: (2.0 ft) x 250 = 500 ft
The area of a rectangle is calculated by multiplying the length and the width.
A = (625 ft)(500 ft) ]= 312,500 ft²
Thus, the area of the actual castle in square feet is 312,500.

8 0

3 years ago

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Can someone help me out here?​

Can someone help me out here?