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ikadub [295]
3 years ago
9

150 adults complete a survey

Mathematics
1 answer:
lesya [120]3 years ago
7 0

Answer:

7 : 8

Step-by-step explanation:

150 adults complete a survey. 80 are women. Thus the ratio of number of men to number of women . Therefore the number of men to number of women be 7 : 8

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vichka [17]

Answer:

4w-15

Step-by-step explanation:

For expressions that have "more than/less than" , that number goes AFTER the "whatever a number" statement because that's just how they explain it. I don't remember the exact reason why, but that is how my professor made me remember it, and yes, the order WILL affect the expression since that's a specific topic and I suppose you're being tested on how to make algebraic expressions based on descriptions.

8 0
3 years ago
PLEASE HELP ASAAP 25 PTS + BRAINLIEST TO RIGHT/BEST ANSWER
Nutka1998 [239]

Let i = sqrt(-1) which is the conventional notation to set up an imaginary number

The idea is to break up the radicand, aka stuff under the square root, to simplify

sqrt(-8) = sqrt(-1*4*2)

sqrt(-8) = sqrt(-1)*sqrt(4)*sqrt(2)

sqrt(-8) = i*2*sqrt(2)

sqrt(-8) = 2i*sqrt(2)

<h3>Answer is choice A</h3>
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3 years ago
PLEASE HELP ASAP WILL MARK BRAINLIEST, SIMPLE MATH PROBLEM
Blizzard [7]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
Use a proof by contradiction to show that the square root of 3 is national You may use the following fact: For any integer kirke
Ierofanga [76]

Answer:

1. Let us proof that √3 is an irrational number, using <em>reductio ad absurdum</em>. Assume that \sqrt{3}=\frac{m}{n} where  m and n are non negative integers, and the fraction \frac{m}{n} is irreducible, i.e., the numbers m and n have no common factors.

Now, squaring the equality at the beginning we get that

3=\frac{m^2}{n^2} (1)

which is equivalent to 3n^2=m^2. From this we can deduce that 3 divides the number m^2, and necessarily 3 must divide m. Thus, m=3p, where p is a non negative integer.

Substituting m=3p into (1), we get

3= \frac{9p^2}{n^2}

which is equivalent to

n^2=3p^2.

Thus, 3 divides n^2 and necessarily 3 must divide n. Hence, n=3q where q is a non negative integer.

Notice that

\frac{m}{n} = \frac{3p}{3q} = \frac{p}{q}.

The above equality means that the fraction \frac{m}{n} is reducible, what contradicts our initial assumption. So, \sqrt{3} is irrational.

2. Let us prove now that the multiplication of an integer and a rational number is a rational number. So, r\in\mathbb{Q}, which is equivalent to say that r=\frac{m}{n} where  m and n are non negative integers. Also, assume that k\in\mathbb{Z}. So, we want to prove that k\cdot r\in\mathbb{Z}. Recall that an integer k can be written as

k=\frac{k}{1}.

Then,

k\cdot r = \frac{k}{1}\frac{m}{n} = \frac{mk}{n}.

Notice that the product mk is an integer. Thus, the fraction \frac{mk}{n} is a rational number. Therefore, k\cdot r\in\mathbb{Q}.

3. Let us prove by <em>reductio ad absurdum</em> that the sum of a rational number and an irrational number is an irrational number. So, we have x is irrational and p\in\mathbb{Q}.

Write q=x+p and let us suppose that q is a rational number. So, we get that

x=q-p.

But the subtraction or addition of two rational numbers is rational too. Then, the number x must be rational too, which is a clear contradiction with our hypothesis. Therefore, x+p is irrational.

7 0
4 years ago
What is the amount of snow that can be placed in this globe if it is 4.7 inches wide?
zepelin [54]

Answer:

The awnswer is D. 54.3in^3

Step-by-step explanation:

7 0
3 years ago
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