Answer:
14
Divide
12 and 1 over 412
1
4
÷ 7 over 8
7
8
= 392 over 28
392
28
Step 1 of 2: Divide, sub-step a: Convert mixed number to improper fraction.
Convert mixed number to improper fraction
12 and 1 over 412
1
4
= ( 12 × 4 ) over 4
12 × 4
4
+ 1 over 4
1
4
= ( 48 + 1 ) over 4
48 + 1
4
= 49 over 4
49
4
Step 1 of 2: Divide, sub-step b: Divide.
Divide
49 over 4
49
4
÷ 7 over 8
7
8
= 49 over 4
49
4
× 8 over 7
8
7
= ( 49 × 8 ) over ( 4 × 7 )
49 × 8
4 × 7
= 392 over 28
392
28
To divide fractions, invert the second one (turn it upside-down), then multiply the numerators and denominators.Divide
12 and 1 over 412
1
4
÷ 7 over 8
7
8
= 392 over 28
392
28
Step 1 of 2: Divide, sub-step a: Convert mixed number to improper fraction.
Convert mixed number to improper fraction
12 and 1 over 412
1
4
= ( 12 × 4 ) over 4
12 × 4
4
+ 1 over 4
1
4
= ( 48 + 1 ) over 4
48 + 1
4
= 49 over 4
49
4
Step 1 of 2: Divide, sub-step b: Divide.
Divide
49 over 4
49
4
÷ 7 over 8
7
8
= 49 over 4
49
4
× 8 over 7
8
7
= ( 49 × 8 ) over ( 4 × 7 )
49 × 8
4 × 7
= 392 over 28
392
28
To divide fractions, invert the second one (turn it upside-down), then multiply the numerators and denominators.
Answer:
32/9
Step-by-step explanation:
Answer:
6 inches
Step-by-step explanation:
It is given that :
Length of the actual car = 8 feet
Width of the actual car is = 4 feet
Michelle is making a model of her car.
The length of her model car = 12 inches
Therefore, the ration is 3 : 2
So the width of the model car = 4 x 3/2
= 6 inches
Answer:
28
Step-by-step explanation:
16 Ada to eves house
12 Eva to pool
28
Answer:
(2, 1)
Step-by-step explanation:
The best way to do this to avoid tedious fractions is to use the addition method (sometimes called the elimination method). We will work to eliminate one of the variables. Since the y values are smaller, let's work to get rid of those. That means we have to have a positive and a negative of the same number so they cancel each other out. We have a 2y and a 3y. The LCM of those numbers is 6, so we will multiply the first equation by a 3 and the second one by a 2. BUT they have to cancel out, so one of those multipliers will have to be negative. I made the 2 negative. Multiplying in the 3 and the -2:
3(-9x + 2y = -16)--> -27x + 6y = -48
-2(19x + 3y = 41)--> -38x - 6y = -82
Now you can see that the 6y and the -6y cancel each other out, leaving us to do the addition of what's left:
-65x = -130 so
x = 2
Now we will go back to either one of the original equations and sub in a 2 for x to solve for y:
19(2) + 3y = 41 so
38 + 3y = 41 and
3y = 3. Therefore,
y = 1
The solution set then is (2, 1)
