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umka21 [38]
4 years ago
14

What is the least positive integer divisible by the numbers 2, 4, and 7?

Mathematics
1 answer:
Viefleur [7K]4 years ago
7 0

Answer:

Least positive integer divisible by the numbers 2, 4, and 7 is  28

Step-by-step explanation:

We can find the least positive integer divisible by the numbers 2, 4, and 7 by taking the LCM

First lets List all prime factors for each number.

Prime Factorization of 2

2 is prime  =>  2^1

Prime Factorization of 4 is:

2 x 2  =>  2^2

Prime Factorization of 7 is:

7 is prime  => 7^1

For each prime factor, find where it occurs most often as a factor and write it that many times in a new list.

The new superset list is

2, 2, 7

Multiply these factors together to find the LCM.

LCM = 2 x 2 x 7 = 28

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goldfiish [28.3K]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
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25/9 converted into a mixed number equals
blagie [28]
First figure out how many times 9 can go into 25 **do the highest amount of times it can go in-
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nine can go in 2 times because 3 times would be way to much
so you're mixed number would be 2
now to figure out you're numerator do 25-18=7
Now it would be 2 7/25
so you're mixed number,then the numerator,finally denomantor ALWAYS stays the same.
                *IF YOU'RE NUMERATOR AND DENOMANTOR CAN BE REDUCED THEN REDUCE</span></span></span>
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