What is the least positive integer divisible by the numbers 2, 4, and 7?
1 answer:
Answer:
Least positive integer divisible by the numbers 2, 4, and 7 is 28
Step-by-step explanation:
We can find the least positive integer divisible by the numbers 2, 4, and 7 by taking the LCM
First lets List all prime factors for each number.
Prime Factorization of 2
2 is prime =>
Prime Factorization of 4 is:
2 x 2 =>
Prime Factorization of 7 is:
7 is prime =>
For each prime factor, find where it occurs most often as a factor and write it that many times in a new list.
The new superset list is
2, 2, 7
Multiply these factors together to find the LCM.
LCM = 2 x 2 x 7 = 28
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SOLUTION
Let us use a simple diagram to interprete the question
In the diagram above, the dark stuff below represents the shadow and the rectangular bar represents the building. I have labelled the height of the building as h.
So we will use the right-angled triangle formed to find h
As we can see h represents the opposite side and 56.5 feet represents the adjacent side of the right-angle triangle. So we will use TOA
So we have
Hence the answer is 104.9 feet to the nearest tenth
