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mixas84 [53]
3 years ago
7

A fruitshake costs R2,00 more than a chocolate milkshake. If 3 fruitshakes and 5 chocolate milkshakes cost R78,00, determine the

individual prices.
Mathematics
2 answers:
lidiya [134]3 years ago
8 0

Answer:

56,00

Step-by-step explanation:

kvv77 [185]3 years ago
3 0

Step-by-step explanation:

Let F represent fruitshake and C chocolate milkshake

one fruitshake cost more 2R more than chocolate shake and

3F + 5C = R78,00

Then (78 - 6) ÷ 8 = 9

a fruitshake costs R11,00 and chocolate milkshake costs 9R,00

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iren2701 [21]
From 8.30 pm to 12 : 00

Difference = 12 : 00 - 08:30 = 3 : 30

3 hours 30 minutes = 3.5 hours.

Total for those hours = 3.5 * 1000 = $3500

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50% increase =  50% of 1000 = .50 * 1000 = 500

So it will increase to 1000 + 500 = $1500 per hour.

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4 years ago
Is .38 greater or less than 3/10
Dominik [7]
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6 0
3 years ago
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Find (a) arc length and (b) Area of a sector.
barxatty [35]

Answer:

a) 29.45 cm (2 dp)

b) 220.89 cm² (2 dp)

Step-by-step explanation:

<u>Formula</u>

\textsf{Arc length}=r \theta

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\quad \textsf{(where r is the radius and}\:\theta\:{\textsf{is the angle in radians)}

<u>Calculation</u>

Given:

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\begin{aligned}\implies \textsf{Arc length} & =r \theta\\& = 15\left(\dfrac{5 \pi}{8}\right)\\& = \dfrac{75}{8} \pi \\& = 29.45\: \sf cm\:(2\:dp)\end{aligned}

\begin{aligned} \implies \textsf{Area of a sector}& =\dfrac{1}{2}r^2 \theta\\\\ & = \dfrac{1}{2}(15^2) \left(\dfrac{5 \pi}{8}\right)\\\\& = \dfrac{225}{2}\left(\dfrac{5 \pi}{8}\right)\\\\ & = \dfrac{1125}{16} \pi \\\\& = 220.89 \: \sf cm^2\:(2\:dp)\end{aligned}

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Answer:

The answer is 5

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Lisa [10]

In this case, u = 20

Hope this helps

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