Help Me graduate bruhh! 6x + 2=2x +2
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The answer is 11.25 mm.
A diameter of a circle is twice of its radius: d = 2r ⇒ r = d/2
small circle large circle
radius: r1 radius: r2 = ?
diameter: d1 = 15 mm
⇒ r1 = d1/2 = 15/2 mm
Since t<span>he ratio of the radii of two circles is 2:3, we have:
r1 : r2 = 2 : 3
which can also be expressed as:
</span>
<span>
We know that r1 is 7.5, so let's implement it:
</span>
Let's multiply both sides of the by 3r2:
⇒
⇒
A diameter of a circle is twice of its radius: d = 2r ⇒ r = d/2
small circle large circle
radius: r1 radius: r2 = ?
diameter: d1 = 15 mm
⇒ r1 = d1/2 = 15/2 mm
Since t<span>he ratio of the radii of two circles is 2:3, we have:
r1 : r2 = 2 : 3
which can also be expressed as:
</span>
<span>
We know that r1 is 7.5, so let's implement it:
</span>
Let's multiply both sides of the by 3r2:
⇒
⇒
the "t" variable is independent, namely it can change values "freely", and a(t) is dependent, because it depends on those values on "t" to get its own value.
if we make a table of values for minutes, we know the balloon is inflating at 6000 ft³ each passing minute.
1 minute......................... 6000(1) ft³
2 minutes......................6000(2) ft³
3 minutes......................6000(3) ft³
4 minutes......................6000(4) ft³
t minutes......................6000(t) ft³
before getting in the domain and range, let's find out how much air after 6 minutes.
a(6) = 6000(6)
a(6) = 36000 ft³.
now, what domain, namely values for "t" make sense?
well, we know the balloon can only hold up to 90000 ft³, and on every passing minute is filling up by 6000 ft³, after how many minutes will it be filled up?
90000/6000 = 15, after 15 minutes.
so at 0 minutes, t = 0, the balloon is empty, and 15 minutes later, t = 15, the balloon is filled up, [ 0 , 15 ].
what values for the range, namely a(t), makes sense?
well, we know when the balloon is empty is holding 0 ft³, and when is full it has 90000 ft³, [0 , 90000].