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agasfer [191]
3 years ago
6

Please Help Question in picture

Mathematics
2 answers:
9966 [12]3 years ago
6 0

Answer:

20

Step-by-step explanation:

Distance formula =

x={sq rt} of (x2-x1)^2 + (y2-y1)^2

{sq rt} (-7-5)^2+ (-7-9)^2 = {sq rt} (-12)^2 + (-16)^2 = {sq rt}

144+256= {sq rt} 400

{sq rt} 400 = 20

(I think its been a hot sec since I did distance formula stuff)

vovangra [49]3 years ago
6 0

Answer:

20

Step-by-step explanation:

You can use the distance formula

sqrt(((5--7)^2)+((9--7)^2)) = 20

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I need help with #5 please
Alika [10]

 

Distance from a point to a line (Coordinate Geometry)

Method 1: When the line is vertical or horizontal , the distance from a point to a vertical or horizontal line can be found by the simple difference of coordinates . Finding the distance from a point to a line is easy if the line is vertical or horizontal. We simply find the difference between the appropriate coordinates of the point and the line. In fact, for vertical lines, this is the only way to do it, since the other methods require the slope of the line, which is undefined for evrtical lines.

Method 2: (If you're looking for an equation) Distance = | Px - Lx |

Hope this helps!

4 0
3 years ago
A 5 kW solor energy system can collect 9000 kWh of energy per year. In Arizona, electricity cost eleven cents per kilowatt hour.
Licemer1 [7]

Answer:

19338 kWh

Step-by-step explanation:

In Arizona, electricity cost eleven cents per kilowatt-hour.

The average home uses 66 million BTU per year i.e. 66000000 BTU per year.

Now, it is given in the question that 1 BTU is equivalent to 0.000293 kWh.

So, the average home uses (66000000 × 0.000293) = 19338 kWh per year.

Therefore, the number of kilowatt-hours used per year will be 19338. (Answer)

6 0
3 years ago
Write the common rule to describe the translation using coordinate notation.
UNO [17]

The common rule is (x - 1, y + 3) can be used to describe the translation.

Step-by-step explanation:

Step 1:

The point J (-3, -4) becomes J^{1} (-4, -1).

In order to write the rule for translation from J to J^{1}, we subtract the x coordinate of J from J^{1} and subtract the y coordinate of J from J^{1}.

The x coordinate = -4-(-3) = -4+3 = -1.

The y coordinate = -1-(-4) = -1+4 = 3.

Step 2:

So from the calculations, we get that the x coordinate is subtracted by 1 i.e. x-1 and the y coordinate is increased by 3 i.e. y+3.

So the common rule is (x - 1, y + 3).

4 0
4 years ago
Oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were millio
JulijaS [17]

Answer:

The amount of oil was decreasing at 69300 barrels, yearly

Step-by-step explanation:

Given

Initial =1\ million

6\ years\ later = 500,000

Required

At what rate did oil decrease when 600000 barrels remain

To do this, we make use of the following notations

t = Time

A = Amount left in the well

So:

\frac{dA}{dt} = kA

Where k represents the constant of proportionality

\frac{dA}{dt} = kA

Multiply both sides by dt/A

\frac{dA}{dt} * \frac{dt}{A} = kA * \frac{dt}{A}

\frac{dA}{A}  = k\ dt

Integrate both sides

\int\ {\frac{dA}{A}  = \int\ {k\ dt}

ln\ A = kt + lnC

Make A, the subject

A = Ce^{kt}

t = 0\ when\ A =1\ million i.e. At initial

So, we have:

A = Ce^{kt}

1000000 = Ce^{k*0}

1000000 = Ce^{0}

1000000 = C*1

1000000 = C

C =1000000

Substitute C =1000000 in A = Ce^{kt}

A = 1000000e^{kt}

To solve for k;

6\ years\ later = 500,000

i.e.

t = 6\ A = 500000

So:

500000= 1000000e^{k*6}

Divide both sides by 1000000

0.5= e^{k*6}

Take natural logarithm (ln) of both sides

ln(0.5) = ln(e^{k*6})

ln(0.5) = k*6

Solve for k

k = \frac{ln(0.5)}{6}

k = \frac{-0.693}{6}

k = -0.1155

Recall that:

\frac{dA}{dt} = kA

Where

\frac{dA}{dt} = Rate

So, when

A = 600000

The rate is:

\frac{dA}{dt} = -0.1155 * 600000

\frac{dA}{dt} = -69300

<em>Hence, the amount of oil was decreasing at 69300 barrels, yearly</em>

7 0
3 years ago
Hello, attached is my problem. Please help!
weqwewe [10]

Answer:

15

Step-by-step explanation:

5 0
3 years ago
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