Answer:
After 3 seconds while going up and 6 seconds while coming down
Step-by-step explanation:
Since projectile is launched from ground level with an initial velocity of v 0 feet per second, initial height =0
Height is given by
where v0 = initial velocity = 144
a) When h =288 ft.
At t= 3 or 6 seconds the projectile would be at height 288 ft.
So while going up after 3 seconds it wouldbe at a height of 288 ft and while coming after 6 seconds.
Answer:
72
Step-by-step explanation:
l = 5w
A = l*w
180 = 5w *w
180 = 5w^2
Divide each side by 5
180/5 = 5w^2 /5
36 = w^2
Taking the square root of each side
sqrt(36) = sqrt(w)^2
6 =w
l = 5w = 5*6 = 30
The perimeter is
P = 2(l+w)
P = 2(6+30) = 2(36) = 72
The division ➗ ÷ sign will make the expression correct if you correct the question!
Answer:
point G : (7,4)
point F : (7,1)
point J : (2,4)
point H: (5,4)
Step-by-steWhen you translate you take each point and move it how many units it asks you to move. In this problen you move each point 7 units to the right and 9 units up to get your answer.
Answer:
Step-by-step explanation:
stop cheating lololololol
