All categories

3 years ago

There are 729 rolls of Ribbon in 9 boxes each box has the same number of rolls of ribbon how many rolls are in each box?

Mathematics

2 answers:

Fittoniya [83]3 years ago

5 0

There are 81 rolls of ribbon in each of the 9 boxes. I can’t see all the options so I hope this helps!

Alex_Xolod [135]3 years ago

3 0

Just divide 729 by 9 = 81

You might be interested in

Which expression is equivalent to x2 - 8x + 15

Valentin [98]

The answer is ( x - 3 ) ( x - 5)

3 0

2 years ago

1986gram=................litters

sladkih [1.3K]

Answer:

I think you have asked a wrong question there should be 1986mililitre or _kg

4 0

2 years ago

You roll a number cube twice first roll is a four second roll I roll a even number is that a defendant or independent situation

Katyanochek1 [597]

Independent because the ratio of the second cube is the same (1:6), and it isn't affected by the result of the first cube

7 0

2 years ago

The half-life of caffeine in a healthy adult is 4.8 hours. Jeremiah drinks 18 ounces of caffeinated

statuscvo [17]

We want to see how long will take a healthy adult to reduce the caffeine in his body to a 60%. We will find that the answer is 3.55 hours.

We know that the half-life of caffeine is 4.8 hours, this means that for a given initial quantity of coffee A, after 4.8 hours that quantity reduces to A/2.

So we can define the proportion of coffee that Jeremiah has in his body as:

P(t) = 1*e^{k*t}

Such that:

P(4.8 h) = 0.5 = 1*e^{k*4.8}

Then, if we apply the natural logarithm we get:

Ln(0.5) = Ln(e^{k*4.8})

Ln(0.5) = k*4.8

Ln(0.5)/4.8 = k = -0.144

Then the equation is:

P(t) = 1*e^{-0.144*t}

Now we want to find the time such that the caffeine in his body is the 60% of what he drank that morning, then we must solve:

P(t) = 0.6 = 1*e^{-0.144*t}

Again, we use the natural logarithm:

Ln(0.6) = Ln(e^{-0.144*t})

Ln(0.6) = -0.144*t

Ln(0.6)/-0.144 = t = 3.55

So after 3.55 hours only the 60% of the coffee that he drank that morning will still be in his body.

If you want to learn more, you can read:

brainly.com/question/19599469

7 0

2 years ago

In how many ways can 4 boys and 4 girls be arranged in a row such that no two boys and no two girls are next to each other?(A) 1

nirvana33 [79]

Answer:

1152

Step-by-step explanation:

4 boys and 4 girls be arranged in a row such that no two boys and no two girls are next to each other.

Two boys and two girls are not next to each other. so one boy and one girl are next to each other in two ways.

BGBGBGBG, GBGBGBGB

4 boys are arranged in 4! ways and 4 girls are arranged in 4! ways

So number of ways = $2 \cdot 4! \cdot 4!=2 \cdot 24 \cdot 24=1152$

4 0

2 years ago