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IgorC [24]
2 years ago
15

For what value of x is line a parallel to line b?

Mathematics
1 answer:
Masja [62]2 years ago
5 0

Answer:

x = 22

Step-by-step explanation:

4x + 28 = 116 (corresponding angles are equal when two lines are parallel)

4x = 88

x = 22

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Devonte used the change of base formula to approximate log Subscript 8 Baseline 25. Which expression did Devonte use?.
scZoUnD [109]

Answer:

I think I did this. I think the answer choices are:

Log StartFraction 8 Over 25 EndFraction

StartFraction log 8 Over log 25 EndFraction

log StartFraction 25 Over 8 EndFraction

----> StartFraction log 25 Over log 8 EndFraction

So the answer is D

Step-by-step explanation:

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Two line are ___ if and only if they lie in the same plane and do not intersect, and two lines are __ if and only if they lie in
Vilka [71]

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Find the equation, (f(x) = a(x - h)2 + k), for a parabola containing point (2, -1) and having (4, -3) as a vertex. What is the s
Nataliya [291]

Answer:

f(x)=\frac{1}{2}x^2-4x+5

Step-by-step explanation:

A parabola is written in the form

f(x)=a((x-h)^2+k) (1)

where:

h is the x-coordinate of the vertex of the parabola

ak is the y-coordinate of the vertex of the parabola

a is a scale factor

For the parabola in the problem, we know that the vertex has  coordinates (4,-3), so we have:

h=4 (2)

ak=-3

From this last equation, we get that a=\frac{-3}{k} (3)

Substituting (2) and (3) into (1) we get the new expression:

f(x)=-\frac{3}{k}((x-4)^2+k) = -\frac{3}{k}(x-4)^2 -3 (4)

We also know that the parabola  contains the point (2,-1), so we can substitute

x = 2

f(x) = -1

Into eq.(4) and find the value of k:

-1=-\frac{3}{k}(2-4)^2-3\\-1=-\frac{3}{k}\cdot 4 -3\\2=-\frac{12}{k}\\k=-\frac{12}{2}=-6

So we also get:

a=-\frac{3}{k}=-\frac{3}{-6}=\frac{1}{2}

So the equation of the parabola is:

f(x)=\frac{1}{2}((x-4)^2 -6) (5)

Now we want to rewrite it in the standard form, i.e. in the form

f(x)=ax^2+bx+c

To do that, we simply rewrite (5) expliciting the various terms, we find:

f(x)=\frac{1}{2}((x^2-8x+16)-6)=\frac{1}{2}(x^2-8x+10)=\frac{1}{2}x^2-4x+5

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Step-by-step explanation:

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