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IgorC [24]
2 years ago
15

For what value of x is line a parallel to line b?

Mathematics
1 answer:
Masja [62]2 years ago
5 0

Answer:

x = 22

Step-by-step explanation:

4x + 28 = 116 (corresponding angles are equal when two lines are parallel)

4x = 88

x = 22

You might be interested in
For which of the following compound inequalities is there no solution? ​
Bess [88]

Answer:

(a)6m \le - 36 and m + 24 > 20

Step-by-step explanation:

Required

Which of a to d has no solution

(a)6m \le - 36 and m + 24 > 20

We have: m + 24 > 20

Sole for m

m >20 - 24

m >-4

6m \le - 36

Divide by 6

m \le -6

So, we have:

m \le -6 and m >-4

m \le -6 implies that: m = -6,-7,-8,-9.....

m >-4 implies that m = -3,-2,-1,0.....

<em>Hence, there is no solution</em>

8 0
3 years ago
Quadrilateral EFGH with diagonals EG and HF must be a parallelogram if (1) EF FG  and GH HE  (2) EG FH  (3) EG FH  (4) EF HG
qwelly [4]

Answer:

EF = HG and EF || HG

Step-by-step explanation:

A quadrilateral is a polygon shape with four sides and four angles.

A parallelogram is a quadrilateral with two pairs of parallel sides. The following are properties of a parallelogram:

  1. Opposite sides are equal and parallel.
  2. Opposite angles are equal to each other.
  3. Consecutive angles are supplementary
  4. The diagonals of a parallelogram bisect each other.

If Quadrilateral EFGH with diagonals EG and HF is a parallelogram then EF = HG and EF || HG

5 0
3 years ago
PLEASE HELP .!!! ILL GIVE BRAINLIEST.. *EXRTA POINTS* .. DONT SKIP :(( ! <br> ILL GIVE 40 POINTS .
RSB [31]

Answer:

x = 5

Step-by-step explanation:

11 = 4x-9

20 = 4x

20/4 = 4x/4

5 = x

5 0
3 years ago
Each year for 4 years, a farmer increased the number of trees in a certain orchard by of the number of trees in the orchard the
Neko [114]

Answer:

The number of trees at the begging of the 4-year period was 2560.

Step-by-step explanation:

Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees wasx+\frac{1}{4} x=\frac{5}{4} x, and for the next three years we have that

                             Start                                          End

Second year     \frac{5}{4}x --------------   \frac{5}{4}x+\frac{1}{4}(\frac{5}{4}x) =\frac{5}{4}x+ \frac{5}{16}x=\frac{25}{16}x=(\frac{5}{4} )^{2}x

Third year    (\frac{5}{4} )^{2}x-------------(\frac{5}{4})^{2}x+\frac{1}{4}((\frac{5}{4})^{2}x) =(\frac{5}{4})^{2}x+\frac{5^{2} }{4^{3} } x=(\frac{5}{4})^{3}x

Fourth year (\frac{5}{4})^{3}x--------------(\frac{5}{4})^{3}x+\frac{1}{4}((\frac{5}{4})^{3}x) =(\frac{5}{4})^{3}x+\frac{5^{3} }{4^{4} } x=(\frac{5}{4})^{4}x.

So  the formula to calculate the number of trees in the fourth year  is  

(\frac{5}{4} )^{4} x, we know that all of the trees thrived and there were 6250 at the end of 4 year period, then  

6250=(\frac{5}{4} )^{4}x⇒x=\frac{6250*4^{4} }{5^{4} }= \frac{10*5^{4}*4^{4} }{5^{4} }=2560.

Therefore the number of trees at the begging of the 4-year period was 2560.  

7 0
3 years ago
Can anyone help with 19-22 with work shown I’m really confused
yanalaym [24]

Answer:

19.  C

20.  D

21.  B

22.  A

Step-by-step explanation:

If an angle is subtended from an arc and it goes to the opposite end of the circle, the angle is HALF of the measure of the arc. If it goes to the center, it is SAME measure as arc.

19.

Arc BC is DOUBLE of Angle BAC, so

78 * 2 = 156

Answer is C

20.

Arc BEC is DOUBLE of Angle BAC, so

114 * 2 = 228

Answer is D

21.

Angle ABC is HALF of Arc AC, so

Angle ABC = 110/2 = 55

Answer is B

22.

Angle ABC is HALF of Arc AC, so

Angle ABC = 218/2 = 109

Answer is A

8 0
3 years ago
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