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kramer
3 years ago
12

One million four hundred ninety-six thousand seven hundred seventy -two in standard form

Mathematics
1 answer:
garik1379 [7]3 years ago
7 0
<span>Greetings!

"One million four hundred ninety-six thousand seven hundred seventy -two in standard form."...

First start at the end of the number:
Two is in the ones place: 2
Seven is in the tens place: 72
Seven is in the hundreds place: 772
Six is in the thousands place: 6772
Nine is in the ten-thousands place: 96772
Four is in the hundred-thousands place: 496772
One is in the millions place: 1</span>496772
 
The number in standard form is: 1496772

Hope this helps.
-Benjamin
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Write the sentence as an equation. The product of r and 338 plus 97 is the same as r.
Vitek1552 [10]

Answer:

Step-by-step explanation:

To write this sentence as equation

We get

r×338+97=r

338r+97=r

To solve further

r-338r=97

-337r=97

r=-0.2878

8 0
3 years ago
2) help ASAP due in like 10min
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The following table shows the possible meal combinations when choosing an entrée and a side dish at Marty's Diner. Side Dish Ent
Dimas [21]

Answer:

5/9

Step-by-step explanation:

There are 9 total combinations and 3 of them include a burger, 2 of them that have salad but not a burger. If you add them together it equals 5/9

6 0
3 years ago
There are 81 cal in a 3/4 cup serving of chicken noodle soup how many calories are in a 2/3 cup serving?
tangare [24]

Answer:

There are 72 cal in 2/3 cup serving of noodle soup

Step-by-step explanation:

The given parameters are;

The amount of calories in 3/4 cup serving of chicken noodle soup = 81 cal

The amount of calories in a 2/3 cup serving is given as follows;

3/4 cup contains 81 cal

1 cup contains 81/(3/4) cal = 81 × 4/3 cal = 108 cal

1 cup contains 108 cal

2/3 cup contains = 2/3 × 1 cup = 2/3 × 108 cal = 72 cal

2/3 cup contains 72 cal

Therefore, there are 72 cal in 2/3 cup serving of noodle soup.

5 0
3 years ago
For the following pair of functions, find (f+g)(x) and (f-g)(x).
ch4aika [34]

Given:

The functions are

f(x)=4x^2+7x-5

g(x)=-9x^2+4x-13

To find:

The functions (f+g)(x) and (f-g)(x).

Solution:

We know that,

(f+g)(x)=f(x)+g(x)

(f+g)(x)=4x^2+7x-5-9x^2+4x-13

(f+g)(x)=(4x^2-9x^2)+(7x+4x)+(-5-13)

(f+g)(x)=-5x^2+11x-18

And,

(f-g)(x)=f(x)-g(x)

(f-g)(x)=(4x^2+7x-5)-(-9x^2+4x-13)

(f+g)(x)=4x^2+7x-5+9x^2-4x+13

(f+g)(x)=(4x^2+9x^2)+(7x-4x)+(-5+13)

(f-g)(x)=13x^2+3x+8

Therefore, the required functions are (f+g)(x)=-5x^2+11x-18

and (f-g)(x)=13x^2+3x+8.

7 0
3 years ago
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